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3 tháng 12 2021
\(\left\{{}\begin{matrix}x-2y=3\\2x+3y=-1\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=3+2y\\2\left(3+2y\right)+3y=-1\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=3+2y\\6+4y+3y=-1\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=3+2y\\7y=-7\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=3+2\left(-1\right)\\y=-1\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=1\\y=-1\end{matrix}\right.\)
3 tháng 12 2021
\(\Leftrightarrow\left\{{}\begin{matrix}2x-4y=6\\2x+3y=-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=-1\\x=3+2y=3-2=1\end{matrix}\right.\)
27 tháng 5 2021
\(\left\{{}\begin{matrix}x+y=500\\\dfrac{8}{10}x+\dfrac{9}{10}y=420\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=500-y\\\dfrac{8}{10}\left(500-y\right)+\dfrac{9}{10}y=420\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=500-y\\400+\dfrac{y}{10}=420\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=500-y=300\\y=200\end{matrix}\right.\)
Vậy (x,y)=(300,200)
PU
27 tháng 5 2021
hpt <=> \(\left\{{}\begin{matrix}\dfrac{8}{10}x+\dfrac{8}{10}y=400\\\dfrac{8}{10}x+\dfrac{9}{10}y=420\end{matrix}\right.\)
<=>\(\left\{{}\begin{matrix}x+y=500\\\dfrac{1}{10}y=20\end{matrix}\right.\)
<=> \(\left\{{}\begin{matrix}x+y=500\\y=200\end{matrix}\right.\)
<=>\(\left\{{}\begin{matrix}x=300\\y=200\end{matrix}\right.\)
HV
1
7 tháng 3 2021
ĐKXĐ: \(x,y\ne0\)\(\left\{{}\begin{matrix}x+y+\dfrac{1}{x}+\dfrac{1}{y}=4\\x^3+y^3+\dfrac{1}{x^3}+\dfrac{1}{y^3}=4\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x+\dfrac{1}{x}+y+\dfrac{1}{y}=4\\\left(x+\dfrac{1}{x}\right)^3+\left(y+\dfrac{1}{y}\right)^3-3\left(x+\dfrac{1}{x}\right)-3\left(y+\dfrac{1}{y}\right)=4\end{matrix}\right.\)
Đặt \(x+\dfrac{1}{x}=a;y+\dfrac{1}{y}=b\left(a,b\ne0\right)\)
\(\Rightarrow hpt\) trở thành:
\(\left\{{}\begin{matrix}a+b=4\left(1\right)\\a^3+b^3-3a-3b=4\left(2\right)\end{matrix}\right.\)
Từ (1) \(\Rightarrow a=4-b\) Thay vào (2) ta được:
\(\left(4-b\right)^3+b^3-3\left(4-b\right)-3b=4\Leftrightarrow64-48b+12b^2-b^3+b^3-12+3b-3b-4=0\Leftrightarrow12b^2-48b+60=0\Leftrightarrow b^2-4b+5=0\Leftrightarrow b^2-4b+4+1=0\Leftrightarrow\left(b-2\right)^2+1=0\) Vô lí \(\Rightarrow\) ko có a,b \(\Rightarrow\) ko có x,y
Vậy hpt vô nghiệm
20 tháng 9 2021
\(c,\left\{{}\begin{matrix}3x+y=10\\4x-3y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}9x+3y=30\\4x-3y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}13x=39\\4x-3y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\y=1\end{matrix}\right.\\ d,\left\{{}\begin{matrix}4x+3y=22\\5x+3y=26\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\5x+3y=26\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\y=2\end{matrix}\right.\\ e,\left\{{}\begin{matrix}4x-3y=5\\5x+3y=13\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}9x=18\\5x+3y=13\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=1\end{matrix}\right.\)
20 tháng 9 2021
c: \(\left\{{}\begin{matrix}3x+y=10\\4x-3y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}12x+4y=40\\12x-9y=27\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}13y=13\\3x+y=10\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=1\\x=3\end{matrix}\right.\)
d: \(\left\{{}\begin{matrix}4x+3y=22\\5x+3y=26\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-x=-4\\4x+3y=22\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\y=\dfrac{22-4x}{3}=\dfrac{22-4\cdot4}{3}=2\end{matrix}\right.\)
20 tháng 9 2021
\(a,\left\{{}\begin{matrix}3x-y=5\\4x+2y=10\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}3x-y=5\\2x+y=5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=1\end{matrix}\right.\\ b,\left\{{}\begin{matrix}5x+2y=9\\x+5y=11\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}5x+2y=9\\5x+25y=55\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}5x+2y=9\\23y=46\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=2\end{matrix}\right.\)
\(c,\left\{{}\begin{matrix}3x+y=10\\4x-3y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}9x+3y=30\\4x-3y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}13x=39\\4x-3y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\y=1\end{matrix}\right.\\ d,\left\{{}\begin{matrix}4x+3y=22\\5x+3y=26\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\5x+3y=26\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\y=2\end{matrix}\right.\)
\(e,\left\{{}\begin{matrix}4x-3y=5\\5x+3y=13\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}9x=18\\5x+3y=13\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=1\end{matrix}\right.\)
HP
20 tháng 9 2021
a. \(\left\{{}\begin{matrix}3x-y=5\\4x+2y=10\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}6x-2y=10\\4x+2y=10\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}10x=20\\6x-2y=10\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=1\end{matrix}\right.\)
b. \(\left\{{}\begin{matrix}5x+2y=9\\x+5y=11\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}5x+2y=9\\5x+25y=55\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}23y=46\\5x+2y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=2\\x=1\end{matrix}\right.\)
c. \(\left\{{}\begin{matrix}3x+y=10\\4x-3y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}9x+3y=30\\4x-3y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}13x=39\\4x-3y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\y=1\end{matrix}\right.\)
d. \(\left\{{}\begin{matrix}4x+3y=22\\5x+3y=26\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\4x+3y=22\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\y=2\end{matrix}\right.\)
e. \(\left\{{}\begin{matrix}4x-3y=5\\5x+3y=13\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}9x=18\\4x-3y=5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=1\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x+y=80\\2x+3y=198\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}3x+3y=240\\2x+3y=198\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x+y=80\\x=240-198=42\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=42\\y=38\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x+y=80\\2x+3y=198\end{matrix}\right.\)
⇔\(\left\{{}\begin{matrix}2x+2y=160\\2x+3y=198\end{matrix}\right.\)
⇔\(\left\{{}\begin{matrix}y=38\\2x+3\cdot38=198\end{matrix}\right.\)
⇔\(\left\{{}\begin{matrix}y=38\\2x=84\end{matrix}\right.\)
⇔\(\left\{{}\begin{matrix}y=38\\x=42\end{matrix}\right.\)
Vậy (42;38) là nghiệm