Question

[Lily Ngô]

GIẢI PHƯƠNG TRÌNH

a)\(\frac{x}{2x-6}+\frac{x}{2x+2}-\frac{2x}{\left(x+1\right)\left(x-3\right)}=0\)

b)\(2x^3-5x^2+3x\)

Các pác giúp iem nhaa

Hứa trả ơn full<3

Answer 1

[★Čүċℓøρş★]

\(a.\frac{x}{2x-6}+\frac{x}{2x+2}-\frac{2x}{\left(x+1\right)\left(x-3\right)}=\)\(0\)

\(\Leftrightarrow\frac{x}{2.\left(x-3\right)}+\frac{x}{2.\left(x+1\right)}-\frac{2x}{\left(x+1\right)\left(x-3\right)}=0\)

\(\Leftrightarrow\frac{x^2+x+x^2-3x-4x}{2.\left(x+1\right).\left(x-3\right)}=0\)

\(\Leftrightarrow2x^2-6=0\)

\(\Leftrightarrow2x^2=6\)

\(\Leftrightarrow x^2=3\)

\(\Leftrightarrow x=\sqrt{3}\)

\(b.2x^3-5x^2+3x=0\)

\(\Leftrightarrow x.\left(2x^2-5x+3\right)=0\)

\(\Leftrightarrow x.\left(2x^2-2x-3x+3\right)=0\)

\(\Leftrightarrow x.\left[2x.\left(x-1\right)-3.\left(x-1\right)\right]=0\)

\(\Leftrightarrow x.\left(x-1\right).\left(2x-3\right)=0\)

Đến đây tự làm nhé có việc bận

Answer 2

[Lily Ngô]

câu a sai dzoii