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up từng bài thôi,nhiều thế ko thánh nào làm cho đâu.thách nhau ak
a) \(x-\dfrac{3}{4}=6\times\dfrac{3}{8}\)
\(x-\dfrac{3}{4}=\dfrac{9}{4}\)
=> \(x=\dfrac{9}{4}+\dfrac{3}{4}=3\)
b) \(\dfrac{7}{8}:x=3-\dfrac{1}{2}\)
\(\dfrac{7}{8}:x=\dfrac{5}{2}\)
=> \(x=\dfrac{7}{8}:\dfrac{5}{2}=\dfrac{7}{20}\)
c) \(x+\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}\)
\(x+\dfrac{1}{6}=\dfrac{3}{4}\)
=> \(x=\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{7}{12}\)
d) \(\dfrac{3}{2}\times\dfrac{4}{5}-x=\dfrac{2}{3}\)
\(\dfrac{6}{5}-x=\dfrac{2}{3}\)
=> \(x=\dfrac{6}{5}-\dfrac{2}{3}=\dfrac{8}{15}\)
e) \(x\times3\dfrac{1}{3}=3\dfrac{1}{3}:4\dfrac{1}{4}\)(?)
\(x\times\dfrac{10}{3}=\dfrac{40}{51}\)
=> \(x=\dfrac{40}{51}:\dfrac{10}{3}=\dfrac{4}{17}\)
f) \(5\dfrac{2}{3}:x=3\dfrac{2}{3}-2\)
\(\dfrac{17}{3}:x=\dfrac{5}{3}\)
=> \(x=\dfrac{17}{3}:\dfrac{5}{3}=\dfrac{17}{5}\)
a: =>x-3/4=18/8=9/4
=>x=9/4+3/4=12/4=3
b: =>7/8:x=5/2
=>x=7/8:5/2=7/8*2/5=14/40=7/20
c: x+1/2*1/3=3/4
=>x+1/6=3/4
=>x=3/4-1/6=9/12-2/12=7/12
d: =>12/10-x=2/3
=>6/5-x=2/3
=>x=6/5-2/3=18/15-10/15=8/15
e: =>x*10/3=10/3:17/4=10/3*4/17
=>x=4/17
f: =>17/3:x=13/3-5/2=26/6-15/6=11/6
=>x=17/3:11/6=17/3*6/11=34/11
\(a,\dfrac{-1}{8}=\dfrac{3}{x}\\ \dfrac{3}{-24}=\dfrac{3}{x}\\ x=-24\\ b,\dfrac{x}{3}=\dfrac{3}{x}\\ x.x=3.3\\ x^2=9\\ x=\pm3\\ c,\dfrac{3}{4}.x=1\dfrac{1}{2}\\ \dfrac{3}{4}.x=\dfrac{3}{2}\\ x=\dfrac{3}{2}:\dfrac{3}{4}\\ x=2\\ d,x-\dfrac{3}{10}=\dfrac{7}{15}:\dfrac{3}{5}\\ x-\dfrac{3}{10}=\dfrac{7}{9}\\ x=\dfrac{7}{9}+\dfrac{3}{10}\\ x=\dfrac{97}{90}\\ e,\dfrac{-4}{7}-x=\dfrac{-8}{3}.\dfrac{3}{7}\\ \dfrac{-4}{7}-x=\dfrac{-8}{7}\\ x=\dfrac{-4}{7}+\dfrac{8}{7}\\ x=\dfrac{4}{7}\\ \)
a) \(x-\dfrac{3}{4}=6.\dfrac{3}{8}=\dfrac{9}{4}\)
\(\Rightarrow x=\dfrac{9}{4}+\dfrac{3}{4}=3\)
c) \(x+\dfrac{1}{2}.\dfrac{1}{3}=\dfrac{3}{4}\)
\(\Rightarrow x+\dfrac{1}{6}=\dfrac{3}{4}\Rightarrow x=\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{9}{12}-\dfrac{2}{12}=\dfrac{7}{12}\)
Bạn xem lại đề c
\(a)-36:x=\frac{30}{7}\)
\(\Rightarrow x=-36:\frac{30}{7}\)
\(\Rightarrow x=-36\cdot\frac{7}{30}\)
\(\Rightarrow x=\frac{-36\cdot7}{30}\)
\(\Rightarrow x=-\frac{126}{15}\)
\(b)\frac{2}{3}\cdot x-\frac{4}{8}=\frac{1}{8}\)
\(\Rightarrow\frac{2}{3}\cdot x=\frac{1}{8}+\frac{4}{8}\)
\(\Rightarrow\frac{2}{3}\cdot x=\frac{5}{8}\)
\(\Rightarrow x=\frac{5}{8}:\frac{2}{3}=\frac{15}{16}\)
\(c)\frac{2}{7}-\frac{8}{9}x=\frac{2}{3}\)
\(\Rightarrow\frac{8}{9}x=\frac{2}{7}-\frac{2}{3}\)
\(\Rightarrow\frac{8}{9}x=\frac{6}{21}-\frac{14}{21}\)
\(\Rightarrow\frac{8}{9}x=\frac{-8}{21}\)
\(\Rightarrow x=\frac{-8}{21}:\frac{8}{9}=\frac{-72}{168}=\frac{-3}{7}\)
d, Tự làm
a) x-3/4=6.3/8
x-3/4=9/4
x=9/4+3/4
x=12/4
Vậy x=3
b) 7/8:x=3-1/2
7/8:x=6/2-1/2
7/8:x=5/4
x=7/8:5/4
x=7/8.5/4
Vậy x=7/10
c) x+1/2.1/3=3/4
x+1/6=3/4
x =3/4-1/6
x = 9/12-2/12
x =8/12
Vậy x=2/3
\(a,\text{ }x-\frac{3}{4}=6\text{ x }\frac{3}{8}\)
\(x-\frac{3}{4}=\frac{9}{4}\)
\(x=\frac{9}{4}+\frac{3}{4}\)
\(x=3\)
\(b,\text{ }\frac{7}{8}\text{ : }x=3-\frac{1}{2}\)
\(\frac{7}{8}\text{ : }x=\frac{5}{2}\)
\(x=\frac{7}{8}\text{ : }\frac{5}{2}\)
\(x=\frac{7}{20}\)
\(c,\text{ }x+\frac{1}{2}\text{ x }\frac{1}{3}=\frac{3}{4}\)
\(x+\frac{1}{6}=\frac{3}{4}\)
\(x=\frac{3}{4}-\frac{1}{6}\)
\(x=\frac{7}{12}\)
240-[23+(13+24.3-x)]=132
240-[23+(13+168-x)]=132
240-[23+(181-x)]=132
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x-8:4-(46-23.2+6.3)=0
\(x-8:4-\left(46-23.2+6.3\right)=0\)
\(x-2-\left(46-46+18\right)=0\)
\(x-2-18=0\)
\(x-2=0+18\)
\(x-2=18\)
\(x=18+2\)
\(x=20\)
a: \(x-\dfrac{3}{4}=6\cdot\dfrac{3}{8}\)
=>\(x-\dfrac{3}{4}=\dfrac{3}{4}\cdot3\)
=>\(x=\dfrac{9}{4}+\dfrac{3}{4}=\dfrac{12}{4}=3\)
b: \(\dfrac{7}{8}:x=3-\dfrac{1}{2}\)
=>\(\dfrac{7}{8}:x=\dfrac{5}{2}\)
=>\(x=\dfrac{7}{8}:\dfrac{5}{2}=\dfrac{7}{8}\cdot\dfrac{2}{5}=\dfrac{7}{20}\)
c: \(x+\dfrac{1}{2}\cdot\dfrac{1}{3}=\dfrac{3}{4}\)
=>\(x+\dfrac{1}{6}=\dfrac{3}{4}\)
=>\(x=\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{9}{12}-\dfrac{2}{12}=\dfrac{7}{12}\)