Question

[Trần Minh Khang]

Tìm \(x\) biết:  

\(\left(\dfrac{3}{4}x-\dfrac{9}{16}\right)\) . \(\left(1,5+\dfrac{-3}{5}:x\right)\) \(=0\)

Answer 1

[HT.Phong (9A5)]

\(\left(\dfrac{3}{4}x-\dfrac{9}{16}\right)\left(1.5+\dfrac{-3}{5}:x\right)=0\left(x\ne0\right)\\ TH1:\dfrac{3}{4}x-\dfrac{9}{16}=0\\ =>\dfrac{3}{4}x=\dfrac{9}{16}\\ =>x=\dfrac{9}{16}:\dfrac{3}{4}=\dfrac{3}{4}\left(tm\right)\\ TH2:1,5+\dfrac{-3}{5}:x=0\\ =>\dfrac{3}{5}:x=\dfrac{3}{2}\\ =>x=\dfrac{3}{5}:\dfrac{3}{2}=\dfrac{2}{5}\left(tm\right)\)

Answer 2

[Trần Xuân Hải]

\(x=\dfrac{3}{4}\) và \(x=\dfrac{2}{5}\)