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LH
2
27 tháng 1 2016
\(\frac{x-17}{33}+\frac{169-x}{23}+\frac{x}{25}=4\)
\(\Rightarrow575.\left(x-17\right)+825.\left(169-x\right)+759x=75900\)
\(\Rightarrow575x-9775+139425-825x+759x-75900=0\)
\(\Rightarrow509x=-53750\)
\(\Rightarrow x=\frac{-53750}{509}\)
TN
27 tháng 1 2016
sử dụng tỉ lệ con nhà bà thức ta có (:|
\(\Leftrightarrow\frac{509x+129650}{18975}=\frac{4}{1}\Rightarrow\left(509x+129650\right)1=18975.4\)
\(\Rightarrow\frac{\left(509x+129650\right)1}{509x}=\frac{18975.4}{509x}\)
\(\Rightarrow\frac{509x+129650}{509x}=\frac{18975.4}{509x}\)
\(\Rightarrow x=-105,599214145383\)
18 tháng 1 2016
a, <=> (x-5/100) -1 +(x-4/101) -1 +(x-3/102) -1= (x-100/5) -1+(x-101/4) -1 +(x-102/3) -1
<=> (x-105)(1/100 +1/101 +1/102)= (x-105)(1/5+1/4+1/3)
<=> (x-105)(1/100+1/101+1/102-1/5-1/4-1/3)=0
vì 1/100+1/101+1/102-1/5-1/4-1/3 khác 0 <=> x-105=0
<=> x=105
18 tháng 1 2016
b, 29-x/21 +1+27-x/23 +1+25-x/25 +1+23-x/27 +1+21-x/29 +1=0
<=> 50-x/21 +50-x/23 +50-x/25 +50-x/27 +50-x/29=0
<=> (50-x)(1/21 +1/23 +1/25 +1/27 +1/29)=0
vì 1/21+1/23+1/25+1/27+1/29 lớn hơn 0
nên 50-x=0
<=> x=50
5 tháng 1 2016
\(\frac{2^{23}\cdot45^{25}\cdot13^{22}\cdot35^{16}}{9^{26}\cdot65^{22}\cdot28^{17}\cdot25^9}=\frac{2^{23}\cdot5^{25}\cdot3^{50}\cdot13^{22}\cdot5^{16}\cdot7^{16}}{3^{52}\cdot5^{22}\cdot13^{22}\cdot7^{17}\cdot2^{54}\cdot5^{18}}=\frac{2^{23}\cdot3^{50}\cdot5^{31}\cdot7^{16}\cdot13^{22}}{2^{54}\cdot3^{52}\cdot5^{22}\cdot7^{17}\cdot13^{22}}=\frac{5^9}{2^{31}\cdot3^2\cdot7}\)
XO
3 tháng 1 2021
a) 3x - 2(5 + 2x) =45 - 2x
=> 3x - 10 - 4x = 45 - 2x
=> 3x - 4x + 2x = 45 + 10
=> x = 55
b) \(\frac{x-3}{5}=6-\frac{1-2x}{3}\)
=> \(\frac{x-3}{5}=\frac{2x+17}{3}\)
=> 5(2x + 17) = 3(x - 3)
=> 10x + 85 = 3x - 9
=> 7x = -94
=> x = -94/7
c) \(\frac{5\left(x-1\right)+2}{6}-\frac{7x-1}{4}=\frac{2\left(2x+1\right)}{7}-5\)
=> \(\frac{5x-3}{6}-\frac{7x-1}{4}=\frac{4x-33}{7}\)
=> \(\frac{10x-6}{12}-\frac{21x-3}{12}=\frac{4x-33}{7}\)
=> \(\frac{-11x-3}{12}=\frac{4x-33}{7}\)
=> (-11x - 3).7 = (4x - 33).12
= -77x - 21 = 48x - 396
=> x = 3
d) (x - 1)(5x + 3) = (3x - 8)(x - 1)
=> (x - 1)(5x + 3) - (3x - 8)(x -1) = 0
=> (x - 1)(2x + 11) = 0
=> \(\orbr{\begin{cases}x-1=0\\2x+11=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\x=-5,5\end{cases}}\)
e) (x - 1)(x2 + 5x - 2) - (x3 - 1) = 0
=> (x - 1)(x2 + 5x - 2) - (x - 1)(x2 + x + 1) = 0
=> (x - 1)(4x - 3) = 0
=> \(\orbr{\begin{cases}x-1=0\\4x-3=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\x=0,75\end{cases}}\)
f) \(\frac{x-17}{33}+\frac{x-21}{29}+\frac{x}{25}=4\)
=> \(\left(\frac{x-17}{33}-1\right)+\left(\frac{x-21}{29}-1\right)+\left(\frac{x}{25}-2\right)=0\)
=> \(\frac{x-50}{33}+\frac{x-50}{29}+\frac{x-50}{25}=0\)
=> \(\left(x-50\right)\left(\frac{1}{33}+\frac{1}{29}+\frac{1}{25}\right)=0\)
=> x - 50 = 0 (Vì \(\frac{1}{33}+\frac{1}{29}+\frac{1}{25}\ne0\))
=> x = 50
3 tháng 1 2021
b, \(\frac{x-3}{5}=6-\frac{1-2x}{3}\)
\(\Leftrightarrow\frac{x-3}{5}=\frac{17+2x}{3}\Leftrightarrow3x-9=85+10x\)
\(\Leftrightarrow-7x=94\Leftrightarrow x=-\frac{94}{7}\)
f, sửa : \(\frac{x+1}{65}+\frac{x+3}{63}=\frac{x+5}{61}+\frac{x+7}{59}\)
\(\Leftrightarrow\frac{x+1}{65}+1+\frac{x+3}{63}+1=\frac{x+5}{61}+1+\frac{x+7}{59}+1\)
\(\Leftrightarrow\frac{x+66}{65}+\frac{x+66}{63}=\frac{x+66}{61}+\frac{x+66}{59}\)
\(\Leftrightarrow\frac{x+66}{65}+\frac{x+66}{63}-\frac{x+66}{61}-\frac{x+66}{59}=0\)
\(\Leftrightarrow\left(x+66\right)\left(\frac{1}{65}+\frac{1}{63}-\frac{1}{61}-\frac{1}{59}\ne0\right)=0\)
\(\Leftrightarrow x=-66\)
NT
2
13 tháng 5 2020
\(\frac{x+9}{11}+\frac{x+23}{25}=\frac{x+6}{4}\)
\(\frac{100x+900}{1100}+\frac{44x+1012}{1100}=\frac{275x+650}{1100}\)
\(100x+900+44x+1012=275x+650\)
\(144x+1912=275x+650\)
\(144x+1912-275x-650=0\)
\(-131x+1262=0\)
\(-131x=-1262\)
\(x=\frac{1262}{131}\)
PN
20 tháng 5 2020
\(\frac{x+9}{11}+\frac{x+23}{25}=\frac{x+6}{4}\)
\(< =>\frac{\left(x+9\right).25+\left(x+23\right).11}{11.25}=\frac{x+6}{4}\)
\(< =>\frac{25x+11x+478}{275}=\frac{x+6}{4}\)
\(< =>\left(36x+478\right).4=\left(x+6\right).275\)
\(< =>144x+1912=275x+1650\)
\(< =>1912-1650=275x-144x=131x\)
\(< =>262=131x\)\(< =>x=\frac{262}{131}=2\)
Sử dụng tỉ lệ thức ta có
\(\Leftrightarrow\frac{18909x+3197000}{18975}=\frac{4}{1}\Rightarrow\left(18909x+3191000\right)\)
\(\Rightarrow\frac{\left(18909x+3197000\right)1}{18909x}=\frac{18975.4}{18909x}\)
\(\Rightarrow\frac{18909x+3197000}{18909x}=\frac{18975.4}{18909x}\)
\(\Rightarrow x\approx-165,05896663\)
đề bài là thế này à:
x - \(\frac{17}{33}\) + 169 - \(\frac{x}{23}\) + \(\frac{x}{25}\) = 4