Question

[Nguyễn Châu Mỹ Linh]

Giải phương trình sau:

a) \(\frac{10}{\left(x+5\right)\left(x-1\right)}+\frac{3}{1-x}=\frac{5}{x+3}\)

b) \(\frac{x-1}{x+2}+\frac{x+3}{x-4}=\frac{2}{\left(x-2\right)\left(4-x\right)}\)

c) \(\frac{7x-3}{x-x^3}=\frac{1}{x-1}-\frac{5}{x\left(x-1\right)}\)

d) \(\frac{1}{x+2}+\frac{1}{x+3}=\frac{1}{\left(x+2\right)\left(x+3\right)}\)

Answer 1

[jungkook jeon]

a,

\(\frac{10}{(x+5)(x-1)}+\frac{3}{x-1}=\frac{5}{x+5}\)

\(\frac{10}{(x+5)(x-1)}+\frac{3(x+5)}{(x+5)(x-1)}=\frac{5(x-1)}{(x+5)(x-1)}\)

\(\Leftrightarrow\)10+3x+15=5x-5

\(\Leftrightarrow\)25+3x=5x-5

\(\Leftrightarrow\)25+3x-5x+5=0

\(\Leftrightarrow\)30-2x=0

\(\Leftrightarrow\)-2x=-30

\(\Leftrightarrow\)x=15

vậy pt có ngiệm là x=15