Question

[Thiên Y]

GIẢI PHƯƠNG TRÌNH (giải giùm, cần gấp ạ) ^^

\(x^3-3x^2+2\sqrt{\left(x+2\right)^3}-6x=0\)

\(x^2+3\sqrt{x^2}-1=\sqrt{x^4-x^2+1}\)

\(\sqrt{5x^2-14x+9}-\sqrt{x^2-x-20}=2\left(x+1\right)\)

\(x^2+\left(3-\sqrt{x^2+2}\right)x=1+2\sqrt{x^2+2}\)

\(\left(x+1\right)\sqrt{x^2-2x+3}=x^2+1\)

Answer 1

[Chu Uyên Như]

sorry! Em moi hoc lop 6.

Answer 2

[Phúc Hồ Thị Ngọc]

a)\(\Leftrightarrow x^3+6x^2+12x+8+2\sqrt{\left(x+2\right)^3}+1-\left(9x^2+18x+9\right)=0\)

\(\Leftrightarrow\left(x+2\right)^3+2\sqrt{\left(x+2\right)^3}+1-\left(3x+3\right)^2=0\)

\(\Leftrightarrow\left(\sqrt{\left(x+2\right)^3}+1\right)^2-\left(3x+3\right)^2=0\)

\(\Leftrightarrow\left(\sqrt{\left(x+2\right)^3}+1+3x+3\right)\left(\sqrt{\left(x+2\right)^3}+1-3x-3\right)=0\)

Đến đây bạn tự giải tiếp nhé