Question

[Shreya]

 giải phương trình chứa ẩn ở mẫu

a/\(\dfrac{5}{3}\)=\(\dfrac{5-3x}{2x}\)

b/\(\dfrac{x-4}{x+1}\)+\(\dfrac{x-1}{x}\)=2

c/\(\dfrac{x+2}{x-2}\)-\(\dfrac{1}{x}\)=\(\dfrac{2}{x\left(x-2\right)}\)

d/\(\dfrac{1}{x}\)+\(\dfrac{3}{x+1}\)=\(\dfrac{2}{x\left(x+1\right)}\)

e/\(\dfrac{x}{x-3}\)+\(\dfrac{x}{x+1}\)=\(\dfrac{2x}{\left(x-3\right)\left(x+1\right)}\)

f/\(\dfrac{2}{x-3}\)-\(\dfrac{4}{x+3}\)=\(\dfrac{5}{x^2-9}\)

Answer 1

[Nguyễn Lê Phước Thịnh]

a: =>10x=3(5-3x)

=>10x=15-9x

=>19x=15

=>x=15/19

b: =>\(\dfrac{x\left(x-4\right)+x^2-1}{x\left(x+1\right)}=2\)

=>2x^2+2x=x^2-4x+x^2-1=2x^2-4x-1

=>2x=-4x-1

=>6x=-1

=>x=-1/6

c:=>x(x+2)-x+2=2

=>x^2+2x-x=0

=>x(x+1)=0

=>x=0(loại) hoặc x=-1(nhận)

d: =>x+1+3x=2

=>4x=1

=>x=1/4

e: =>x(x+1)+x(x-3)=2x

=>x^2+x+x^2-3x=2x

=>2x^2-4x=0

=>x=0(nhận) hoặc x=2(nhận)

f: =>2x+6-4x+12=5

=>-2x=-13

=>x=13/2