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\(a,4^{2x-6}=1\)\(\Leftrightarrow2x-6=0\Leftrightarrow2x=6\Rightarrow x=3\)
\(b,2^{2x-1}=16\Rightarrow2^{2x-1}=2^4\)
\(\Rightarrow2x-1=4\Rightarrow2x=5\Rightarrow x=\frac{5}{2}\)
\(c,5< 5^x< 125\Rightarrow5^1< 5^x< 5^3\)\(\Rightarrow1< x< 3\)
\(d,5^{x+1}=125\Rightarrow5^{x+1}=5^3\Rightarrow x+1=3\Rightarrow x=2\)
\(a,4^{2x-6}=1\)
\(4^{2x-6}=4^0\)
\(\Rightarrow2x-6=0\)
\(\Rightarrow2x=6\Leftrightarrow x=3\)
\(b,2^{x-1}=16\)
\(2^{x-1}=2^4\)
\(\Rightarrow x-1=4\)
\(\Rightarrow x=5\)
\(\left(5^{2x+x+1}\right)=125.5=625\)
\(5^{3x}.5=625\)
\(5^{3x}=125\)
\(125^x=125\)
\(\Rightarrow x=1\)
(52x.5x+1):5=125
(52x.5x+1)= 125.5
(52x.5x+1)=625
\(5^{3x}=125\Rightarrow125^x=125=>x=1\)
\(5^{2x+1} = 125 . 5^2 => 5^{2x+1} = 5^3 . 5^2 => 5^{2x+1} = 5^5 => 2x + 1 = 5 => 2x = 5-1 => 2 x = 4 => x = 4 : 2 => x = 2 \)
a.
(2x+1)2 = 25 = 52
=> 2x + 1 = 5
=> 2x = 4
=> x = 2
Vậy x = 2
b.
52x+1 = 125 = 53
=> 2x + 1 = 3
=> 2x = 2
=> x = 1
Vậy x = 1
Chúc em học tốt!!!
a) 2x . 4 = 128
<=> 2x = 32
<=> 2x = 25
<=> x = 5
b) x15 = x1
<=> x15 - x = 0
<=> x(x14 - 1) = 0
<=> \(\orbr{\begin{cases}x=0\\x^{14}-1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x^{14}=1^{14}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=\pm1\end{cases}}\)
c) (2x + 1)3 = 125
<=> (2x + 1)3 = 53
<=> 2x + 1 = 5
<=> 2x = 4
<=> x = 2
d) (x - 5)4 = (x - 5)6
<=> (x - 5)6 - (x - 5)4 = 0
<=> (x - 5)4[(x - 5)2 - 1] = 0
<=> \(\orbr{\begin{cases}\left(x-5\right)^4=0\\\left(x-5\right)^2-1=0\end{cases}}\)
Khi (x - 5)4 = 0 => x - 5 = 0 => x = 5
Khi (x - 5)2 - 1 = 0 <=> (x - 5)2 = 12 <=> \(\orbr{\begin{cases}x-5=1\\x-5=-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=6\\x=4\end{cases}}\)
\(5^{2x}.5^{x+1}:5=125\)
\(\Rightarrow5^{2x}.5^x.5:5=125\)
\(\Rightarrow5^{2x}.5^x=125\)
\(\Rightarrow5^{3x}=125\)
\(\Rightarrow5^{3x}=5^3\)
\(\Rightarrow3x=3\)\(\Rightarrow x=1\)
Vậy : x = 1
a) \(\left(2x-1\right)^5=243\)
\(\left(2x-1\right)^5=3^5\)
\(\Rightarrow2x-1=3\)
\(2x=3+1\)
\(2x=4\)
\(x=\frac{4}{2}\)
\(x=2\)
Vậy .......
b) \(\left(3x+2\right)^3=125\)
\(\left(3x+2\right)^3=5^3\)
\(\Rightarrow3x+2=5\)
\(3x=5-2\)
\(3x=3\)
\(x=\frac{3}{3}=1\)
Vậy ..........
\(5^{2x-1}=125\\ =>5^{2x-1}=5^3\\ =>2x-1=3\\ =>2x=3+1\\ =>2x=4\\ =>x=\dfrac{4}{2}\\ =>x=2\)
Vậy: ...
52x - 1 = 125
52x - 1 = 53
2x - 1 = 3
2x = 3 +1
2x = 4
x = 4 :2
x = 2