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\(2^x+2^{x+1}+2^{x+2}=224\)
\(\Rightarrow2^x\times\left(1+2+4\right)=224\)
\(\Leftrightarrow2^x\times7=224\)
\(\Leftrightarrow2^x=224\div7\)
\(\Rightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Rightarrow x=5\)
vậy \(x=5\)
\(2^x+2^{x+1}+2^{x+2}=224\)
\(7.2^x=224\)
\(\frac{7.2^x}{7}=\frac{224}{7}\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
Câu a
=> 3.3^x + (3+2+1) = 9477 => 3.3^x = 9471 => 3^x = 9471/3 = 3157 => x= ... có viết sai đb ko hả?
Câu b
x^2 + 54 - 42 = 112 => x^2 + 12 = 112 => x^2 = 100 => x = 10 hoặc -10
2x-1+2x+2x+1=224
2x:2+2x+2x.2=224
2x.\(\frac{1}{2}\)+2x+2x.2=224
\(2^x.\left(\frac{1}{2}+1+2\right)=224\)
\(2^x.\frac{7}{2}=224\)
\(2^x=224:\frac{7}{2}\)
\(2^x=64\)
2x=26
=> x=6
Vậy x=6
|x+3|=|x-5|
\(\Rightarrow\orbr{\begin{cases}x+3=x-5\\x+3=-x+5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x-x=-5-3\Rightarrow0x=-8\left(vl\right)\\x+x=5-3\Rightarrow2x=2\Rightarrow x=2:2=1\end{cases}}\)
Vậy x=1
2x + 2x+1 + 2x+2 =224
<=>2x(1+2+4)=224
<=>2x.7=224
<=>2x=32
<=>x=5
vậy x=5
\(=>2^x+2^x.2^1+2^x.2^2=224\)
=> \(2^x+2^x.2+2^x.4=224\)
=> x = 5
a,x2.x3=25
=>x5=25
=>x=2
b,x+18=5.4^2
=>x=5.16-18
=>x=62
c,x.(x^2)^3=x^5
=>x.x5=x5
=>x=0,1
d,2x.7=224
2x=32
=>2x=25
=>x=5
e,(3x+5)2=289
=>(3x+5)2=172
=>3x+5=17
=>3x=12
=>x=4
g,32x+1.11=2673
=>32x=243
=>32x=35
=>x=\(\frac{5}{2}\)
\(2^{x+2}+2^{x+2}+2^{x+1}=224\\ =>2^{x+1}\cdot2+2^{x+1}\cdot2+2^{x+1}\cdot1=224\\ =>2^{x+1}\cdot\left(2+2+1\right)=224\\ =>2^{x+1}\cdot5=224\\ =>2^{x+1}=\dfrac{224}{5}\\ =>x+1=log_2\dfrac{224}{5}\\ =>x=log_2\dfrac{224}{5}-1\)