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a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)
\(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\cdot\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{1-10}{6}-\dfrac{20}{3}\cdot\dfrac{8-5}{20}+\dfrac{2}{3}\cdot\dfrac{12-45}{10}\)
\(=\dfrac{-1}{2}\cdot\dfrac{-9}{6}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{66}{30}=\dfrac{-1}{4}-\dfrac{11}{5}=\dfrac{-5-44}{20}=-\dfrac{49}{20}\)
\(a,\left(\frac{3}{8}+-\frac{3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
= \(\left(-\frac{3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
= \(\frac{5}{24}:\frac{5}{6}+\frac{1}{2}\)
= \(\frac{1}{4}+\frac{1}{2}\)
= \(\frac{3}{4}\)
b)\(-\frac{7}{3}.\frac{5}{9}+\frac{4}{9}.\left(-\frac{3}{7}\right)+\frac{17}{7}\)
=\(-\frac{35}{27}+\left(-\frac{4}{21}\right)+\frac{17}{7}\)
= \(-\frac{35}{27}+\frac{47}{21}\)
= \(\frac{178}{189}\)
c) \(\frac{117}{13}-\left(\frac{2}{5}+\frac{57}{13}\right)\)
= \(\frac{117}{13}-\frac{311}{65}\)
= \(\frac{274}{65}\)
d) \(\frac{2}{3}-0,25:\frac{3}{4}+\frac{5}{8}.4\)
= \(\frac{2}{3}-\frac{1}{4}:\frac{3}{4}+\frac{5}{8}.4\)
= \(\frac{2}{3}-\frac{1}{3}+\frac{5}{2}\)
= \(\frac{1}{3}+\frac{5}{2}\)
= \(\frac{17}{6}\)
Bài 1:
a,\(0,75+\frac{9}{17}-1\frac{4}{5}-\frac{26}{17}-2\frac{4}{5}\)
\(=\frac{3}{4}+\left(\frac{9}{17}-\frac{26}{17}\right)-\left(1\frac{4}{5}+2\frac{4}{5}\right)\)
\(=\frac{3}{4}-1-\frac{23}{5}\)
\(=\frac{15}{20}-\frac{20}{20}-\frac{92}{20}=\frac{-97}{20}\)
Bài 2:
a, \(\left(2x+\frac{3}{4}\right)-\frac{10}{3}=\frac{-13}{3}\)
\(2x+\frac{3}{4}=\frac{-13}{3}+\frac{10}{3}\)
\(2x+\frac{3}{4}=-1\)
\(2x=-1-\frac{3}{4}\)
\(2x=\frac{-7}{4}\)
x = -7/8
b, 3,2x - 2,7x + 8,5 = 6
x(3,2 - 2,7) = -2,5
0,5x = -2,5
x = -5
a
\(-\frac{16}{17}< -\frac{14}{17}< -\frac{12}{17}< -\frac{11}{17}< -\frac{9}{17}< -\frac{3}{17}< -\frac{1}{17}\)
b
\(-\frac{5}{2}< -\frac{5}{3}< -\frac{5}{4}< -\frac{5}{7}< -\frac{5}{8}< -\frac{5}{9}< -\frac{5}{11}\)
P/S:Lẽ ra ko lm bài này nhưng thấy chứ đang vội thì lm nốt:((
a) Vì -16 < -14 < -12 < -11 < -9 < -3 < -1
=> \(\frac{-16}{17}\), \(\frac{-14}{17}\), \(\frac{-12}{17}\), \(\frac{-11}{17}\), \(\frac{-9}{17}\), \(\frac{-3}{17}\), \(\frac{-1}{17}\)
b) Vì 2 < 3 < 4 < 7 < 8 < 9 < 11
mà theo lí thuyết ta có : phân số nào có mẫu lớn hơn thì phân số đó bé hơn và ngược lại
=> \(\frac{-5}{11}\), \(\frac{-5}{9}\), \(\frac{-5}{8}\), \(\frac{-5}{7}\), \(\frac{-5}{4}\), \(\frac{-5}{3}\), \(\frac{-5}{2}\)
~ Học tốt ~
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\(-\dfrac{3}{16}+-\dfrac{3}{8}-\dfrac{5}{4}\)
\(=-\dfrac{3}{16}-\dfrac{3}{8}-\dfrac{5}{4}\)
\(=-\dfrac{3}{16}-\dfrac{6}{16}-\dfrac{20}{16}\)
\(=\dfrac{-3-6-20}{16}\)
\(=-\dfrac{29}{16}\)
\(\left(-\dfrac{25}{13}\right)+\dfrac{-9}{17}+\dfrac{12}{13}+\dfrac{25}{17}\)
\(=\left[\left(-\dfrac{25}{13}\right)+\dfrac{12}{13}\right]+\left[\left(-\dfrac{9}{17}+\dfrac{25}{17}\right)\right]\)
\(=-\dfrac{13}{13}+\dfrac{17}{17}\)
\(=-1+1\)
\(=0\)
`5/9 + 4/9 . 8/17 + 4/9 . 1/17 - 4/9 . 26/17`
` = 5/9 + 4/9 . (8/17 + 1/17 - 26/17)`
` = 5/9 + 4/9 . (-1)`
` = 5/9 + (-4/9)`
` = 1/9`