Câu hỏi của Nguyễn Hoài Phương

Question

2 l 1/2 -3/4 l + căn bậc hai của 4/9

HT.Phong (9A5) · Accepted Answer

$2\left|\dfrac{1}{2}-\dfrac{3}{4}\right|+\sqrt{\dfrac{4}{9}}\
=2\left|\dfrac{2}{4}-\dfrac{3}{4}\right|+\sqrt{\left(\dfrac{2}{3}\right)^2}\
=2\left|\dfrac{-1}{4}\right|+\dfrac{2}{3}\
=2\cdot\dfrac{1}{4}+\dfrac{2}{3}\
=\dfrac{1}{2}+\dfrac{2}{3}\
=\dfrac{7}{6}$Câu trả lời: $2\left|\dfrac{1}{2}-\dfrac{3}{4}\right|+\sqrt{\dfrac{4}{9}}\
=2\left|\dfrac{2}{4}-\dfrac{3}{4}\right|+\sqrt{\left(\dfrac{2}{3}\right)^2}\
=2\left|\dfrac{-1}{4}\right|+\dfrac{2}{3}\
=2\cdot\dfrac{1}{4}+\dfrac{2}{3}\
=\dfrac{1}{2}+\dfrac{2}{3}\
=\dfrac{7}{6}$

Nguyễn An Ninh · Answer

$2\left|\dfrac{1}{2}-\dfrac{3}{4}\right|+\sqrt{\dfrac{4}{9}}$

$=2\left|\dfrac{2}{4}-\dfrac{3}{4}\right|+\sqrt{\left(\dfrac{2}{3}\right)^2}$

$=2\left|-\dfrac{1}{4}\right|+\dfrac{2}{3}$

$=2\cdot\dfrac{1}{4}+\dfrac{2}{3}$

$=\dfrac{1}{2}+\dfrac{2}{3}$

$=\dfrac{3}{6}+\dfrac{4}{6}$

$=\dfrac{7}{6}$Câu trả lời: $2\left|\dfrac{1}{2}-\dfrac{3}{4}\right|+\sqrt{\dfrac{4}{9}}$

$=2\left|\dfrac{2}{4}-\dfrac{3}{4}\right|+\sqrt{\left(\dfrac{2}{3}\right)^2}$

$=2\left|-\dfrac{1}{4}\right|+\dfrac{2}{3}$

$=2\cdot\dfrac{1}{4}+\dfrac{2}{3}$

$=\dfrac{1}{2}+\dfrac{2}{3}$

$=\dfrac{3}{6}+\dfrac{4}{6}$

$=\dfrac{7}{6}$

Chúng tôi đề xuất

Tài nguyên

Ứng dụng mobile

Bảng xếp hạng

Các khóa học có thể bạn quan tâm

Yêu cầu VIP