Question

[Realm of Valor]

Gia tri(x)	6	8	9	10
Tan so(n)	5	a	3	1

tim a biet diem TBC bang 7,5

Answer 1

[ST]

Ta ó: \(\frac{6.5+8a+9.3+10.1}{5+a+3+1}=7,5\)

\(\Rightarrow\frac{67+8a}{9+a}=7,5\)

\(\Rightarrow67+8a=7,5\left(9+a\right)\)

\(\Rightarrow67+8a=67,5+7,5a\)

\(\Rightarrow8a-7,5a=67,5-67\)

=> 0,5a = 0,5

=> a = 1