Question

[hồng minh nguyễn]

giá trị tuyệt đối x 2010 giá trị tuyệt đối x-2011 = 2012

Answer 1

[Nguyễn Hoàng Minh]

\(\left|x-2010\right|+\left|x-2011\right|=2012\\ \Rightarrow\left[{}\begin{matrix}2010-x+2011-x=2012\left(x< 2010\right)\\x-2010+2011-x=2012\left(2010\le x< 2011\right)\\x-2010+x-2011=2012\left(x\ge2011\right)\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{2009}{2}\left(tm\right)\\0x=2011\left(vô.lí\right)\\x=\dfrac{6033}{2}\left(tm\right)\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{2009}{2}\\x=\dfrac{6033}{2}\end{matrix}\right.\)