Question

[Đỗ Thị Mai Chi]

\(\frac{x+1}{2015}\)+\(\frac{x+2}{2014}\) =\(\frac{x+3}{2013}\)+\(\frac{x+4}{2012}\)(tìm các giá trị của x thỏa mãn x thuộc z)

có ai làm được ko lam giup minh voi

Answer 1

[Minh Anh]

\(\frac{x+1}{2015}+\frac{x+2}{2014}=\frac{x+3}{2013}+\frac{x+4}{2012}\)

\(\Leftrightarrow\frac{x+1}{2015}+1+\frac{x+2}{2014}+1=\frac{x+3}{2013}+1+\frac{x+4}{2012}+1\)

\(\Leftrightarrow\frac{x+2016}{2015}+\frac{x+2016}{2014}=\frac{x+2016}{2013}+\frac{x+2016}{2012}\)

\(\Leftrightarrow\frac{x+2016}{2015}+\frac{x+2016}{2014}-\frac{x+2016}{2013}-\frac{x+2016}{2012}=0\)

\(\Leftrightarrow\left(x+2016\right)\left(\frac{1}{2015}+\frac{1}{2014}-\frac{1}{2013}-\frac{1}{2012}\right)=0\)

Có: \(\frac{1}{2015}+\frac{1}{2014}-\frac{1}{2013}-\frac{1}{2012}\ne0\)

 \(\Rightarrow x+2016=0\)

\(\Rightarrow x=-2016\)