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\(\frac{x-5}{3}=\frac{6}{5}\)
\(x-5=\frac{6}{5}.3\)
\(x-5=\frac{18}{5}\)
\(x=\frac{18}{5}+5\)
\(\Rightarrow x=\frac{43}{5}\)
Vậy ...
\(\frac{1}{3}=\frac{2-x}{4}\)
\(\frac{4}{3}=2-x\)
\(x=2-\frac{4}{3}\)
\(\Rightarrow x=\frac{2}{3}\)
Vậy ...
\(\frac{x-2}{4}=\frac{5+x}{3}\)
\(\Rightarrow3\left(x-2\right)=4\left(5+x\right)\)
\(\Rightarrow3x-6=20+4x\)
\(\Rightarrow3x-4x=20+6\)
\(\Rightarrow3x-4x=26\)
\(\Rightarrow-x=26\Rightarrow x=-26\)
\(-x-\frac{3}{4}=-\frac{8}{11}=>-x=-\frac{8}{11}+\frac{3}{4}=\frac{1}{44}=>x=-\frac{1}{44}\)
\(a)x+30\%x=-1,31\)
\(\Leftrightarrow x+\frac{3x}{10}=-1,31\)
\(\Leftrightarrow10x+3x=-13,1\)
\(\Leftrightarrow13x=-13,1\Leftrightarrow x=-\frac{131}{130}\)
\(b)\left(x-\frac{1}{2}\right):\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)
\(\Leftrightarrow\frac{2x-1}{2}.3+\frac{5}{7}=\frac{68}{7}\)
\(\Leftrightarrow\frac{6x-3}{2}=\frac{63}{7}\)
\(\Leftrightarrow\frac{6x-3}{2}=9\)
\(\Leftrightarrow6x-3=18\)
\(\Leftrightarrow x=\frac{7}{2}\)
\(\frac{5}{3}x-\frac{2}{5}x=\frac{19}{10}\)
\(\left(\frac{5}{3}-\frac{2}{5}\right)x=\frac{19}{10}\)
\(\frac{19}{15}x=\frac{19}{10}\)
\(x=\frac{19}{30}\)
\(\frac{5}{3}x-\frac{2}{5}x=\frac{19}{10}\)
(5/3 - 2/5)x = 19/10
19/15x = 19/10
x = 19/30
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