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27 tháng 3 2016
  1.  

đặt 6 ở tử làm thừa số chung và 8 ở mẫu làm thừa số chung.rút gọn ta được kq là 6/8=3/4

12 tháng 3 2016

\(\frac{\frac{6}{7}-\frac{6}{9}+\frac{6}{11}-\frac{6}{13}}{\frac{8}{7}-\frac{8}{9}+\frac{8}{11}-\frac{8}{13}}\)

=\(\frac{6.\left(\frac{1}{7}-\frac{1}{9}+\frac{1}{11}-\frac{1}{13}\right)}{8.\left(\frac{1}{7}-\frac{1}{9}+\frac{1}{11}-\frac{1}{13}\right)}\)

=\(\frac{6}{8}\)

=\(\frac{3}{4}\)

12 tháng 3 2016

có z ko tính đk s p hỏi

tính tử òi tính mẫu òi tính cả thế nhé 

31 tháng 7 2015

\(E=\frac{6\left(\frac{1}{7}-\frac{1}{9}+\frac{1}{11}-\frac{1}{13}\right)}{8\left(\frac{1}{7}-\frac{1}{9}+\frac{1}{11}-\frac{1}{13}\right)}=\frac{6}{8}=\frac{3}{4}\)

Bài 1:

a) Ta có: \(\frac{8}{40}+\frac{-4}{20}-\frac{3}{5}\)

\(=\frac{1}{5}+\frac{-1}{5}-\frac{3}{5}\)

\(=\frac{-3}{5}\)

b) Ta có: \(\frac{-7}{12}+\frac{-2}{12}-\frac{-3}{36}\)

\(=\frac{-7}{12}+\frac{-2}{12}-\frac{-1}{12}\)

\(=\frac{-9+1}{12}=\frac{-8}{12}=\frac{-2}{3}\)

c) Ta có: \(\left(\frac{1}{6}+\frac{-4}{13}\right)-\left(-\frac{17}{6}-\frac{30}{13}\right)\)

\(=\frac{1}{6}+\frac{-4}{13}+\frac{17}{6}+\frac{30}{13}\)

\(=3+2=5\)

d) Ta có: \(-\frac{-5}{4}+\frac{7}{4}-\frac{-11}{7}+\frac{2}{7}\)

\(=\frac{5}{4}+\frac{7}{4}+\frac{11}{7}+\frac{2}{7}\)

\(=3+\frac{13}{7}=\frac{21}{7}+\frac{13}{7}=\frac{34}{7}\)

e) Ta có: \(-\frac{1}{8}+\frac{-7}{9}+\frac{-7}{8}+\frac{6}{7}+\frac{2}{14}\)

\(=-1+1+\frac{-7}{9}\)

\(=-\frac{7}{9}\)

f) Ta có: \(\frac{-2}{9}-\frac{11}{-9}+\frac{5}{7}-\frac{-6}{-7}\)

\(=\frac{-2-\left(-11\right)}{9}+\frac{5-6}{7}\)

\(=1+\frac{-1}{7}=\frac{7}{7}+\frac{-1}{7}=\frac{6}{7}\)

Tính :

a) \(\frac{1}{6}.\frac{9}{-8}.\left(-\frac{12}{11}\right)=\frac{1.9.\left(-12\right)}{6.\left(-8\right).11}=\frac{1.3.3}{2.2.11}=\frac{9}{44}\)

b) \(\frac{1}{8}.\frac{-3}{7}+\frac{1}{8}.\frac{-4}{7}\)

\(=\frac{1}{8}.\left(-\frac{3}{7}+\frac{-4}{7}\right)\)

\(=\frac{1}{8}.\frac{-7}{7}=\frac{1}{8}.\left(-1\right)\)

\(=-\frac{1}{8}\)

c) \(\frac{7}{13}.\frac{3}{-5}+\frac{6}{13}.\frac{-3}{5}\)

\(=-\frac{3}{5}.\left(\frac{7}{13}+\frac{6}{13}\right)\)

\(=-\frac{3}{5}.\frac{13}{13}=-\frac{3}{5}.1\)

\(=-\frac{3}{5}\)

5 tháng 8 2019

a, \(\frac{1}{6}.\frac{9}{-8}.\frac{-12}{11}\)

\(\Rightarrow\frac{9}{8}.\frac{2}{11}\)

\(\Rightarrow\frac{9}{4}.\frac{1}{11}\)

\(\Rightarrow\frac{9}{44}\)

b,\(\frac{1}{8}.\frac{-3}{7}+\frac{1}{8}.\frac{-4}{7}\)

\(\Rightarrow\frac{-3}{56}-\frac{1}{2}.\frac{1}{7}\)

\(\Rightarrow\frac{-3}{56}-\frac{1}{2}.\frac{1}{7}\)

\(\Rightarrow\frac{-3}{56}-\frac{1}{14}\)

\(\Rightarrow\frac{-1}{8}\)

c,\(\frac{7}{13}.\frac{3}{-5}+\frac{6}{13}.\frac{-3}{5}\)

\(\Rightarrow\frac{-21}{65}-\frac{18}{65}\)

\(\Rightarrow\frac{-3}{5}\)

a: \(=-9+\left\{-52:9\right\}=-9+\dfrac{-52}{9}=-\dfrac{133}{9}\)

b: \(=\dfrac{17}{7}+\left(\dfrac{-76}{63}\right):15\)

\(=\dfrac{17}{7}-\dfrac{76}{63}\cdot\dfrac{1}{15}=\dfrac{317}{135}\)

e: \(=\dfrac{-5}{13}\cdot\dfrac{7}{3}-\dfrac{2}{7}\cdot\dfrac{8}{13}+\dfrac{5}{13}\cdot\dfrac{1}{7}\)

\(=\dfrac{5}{13}\left(-\dfrac{7}{3}+\dfrac{1}{7}\right)-\dfrac{2}{7}\cdot\dfrac{8}{13}\)

\(=\dfrac{5}{13}\cdot\dfrac{-46}{21}-\dfrac{16}{91}=\dfrac{-278}{273}\)

10 tháng 3 2018

\(P=\frac{6}{7}.\frac{8}{13}+\frac{6}{9}.\frac{9}{7}-\frac{3}{13}.\frac{6}{7}\)

\(P=\frac{6}{7}.\frac{8}{13}+\frac{6}{7}-\frac{3}{13}.\frac{6}{7}\)

\(P=\frac{6}{7}.\left(\frac{8}{13}+1-\frac{3}{13}\right)\)

\(P=\frac{6}{7}.\frac{18}{13}\)

\(P=\frac{108}{91}\)

10 tháng 3 2018

\(\frac{6}{7}.\frac{8}{13}+\frac{6}{9}.\frac{9}{7}-\frac{3}{13}.\frac{6}{7}\)

\(\frac{6}{7}.\left(\frac{8}{13}-\frac{3}{13}\right)+\frac{6}{9}.\frac{9}{7}\)

\(\frac{6}{7}.\frac{5}{13}+\frac{54}{63}\)

\(\frac{30}{91}+\frac{54}{63}\)

\(\frac{30}{91}+\frac{6}{7}\)

\(\frac{30}{91}+\frac{78}{91}\)

\(\frac{108}{91}\)

9 tháng 3 2017

a) \(\frac{1}{9}\)

b) -1100