Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(\frac{-77}{143}+\frac{65}{143}-\frac{66}{143}+\frac{7}{22}\)
= \(\frac{-78}{143}+\frac{7}{22}\)= \(\frac{-6}{11}+\frac{7}{22}\)= \(\frac{-12}{22}+\frac{7}{22}\)
= \(\frac{-5}{22}\)
b) \(\frac{-4}{5}-\frac{20}{170}+\frac{51}{170}+\frac{150}{170}\)= \(\frac{-4}{5}-\frac{221}{170}\)
\(\frac{-4}{5}-\frac{13}{10}\)= \(\frac{-8}{10}-\frac{13}{10}\)=\(\frac{-21}{10}\)
-4/5 + 1/-5 = -1 => -4/5 + 1/-5 = -1
-13/22 + -7/22 = -10/11 => -13/22 + -7/22 < -8/11 (vì -10 < -8)
2/3 + -1/5 = 7/15 ; 3/5 = 9/15 => 3/5 > 2/3 + -1/5 (vì 9 >7)
\(\begin{array}{l}a)\left( {\frac{2}{3} + \frac{1}{6}} \right):\frac{5}{4} + \left( {\frac{1}{4} + \frac{3}{8}} \right):\frac{5}{2}\\ = \left( {\frac{4}{6} + \frac{1}{6}} \right).\frac{4}{5} + \left( {\frac{2}{8} + \frac{3}{8}} \right).\frac{2}{5}\\ = \frac{5}{6}.\frac{4}{5} + \frac{5}{8}.\frac{2}{5}\\ = \frac{2}{3} + \frac{1}{4}\\ = \frac{8}{{12}} + \frac{3}{{12}}\\ = \frac{{11}}{{12}}\\b)\frac{5}{9}:\left( {\frac{1}{{11}} - \frac{5}{{22}}} \right) + \frac{7}{4}.\left( {\frac{1}{{14}} - \frac{2}{7}} \right)\\ = \frac{5}{9}:\left( {\frac{2}{{22}} - \frac{5}{{22}}} \right) + \frac{7}{4}.\left( {\frac{1}{{14}} - \frac{4}{{14}}} \right)\\ = \frac{5}{9}:\frac{{ - 3}}{{22}} + \frac{7}{4}.\frac{{ - 3}}{{14}}\\ = \frac{5}{9}.\frac{{ - 22}}{3} + \frac{{ - 3}}{8}\\ = \frac{{ - 110}}{{27}} + \frac{{ - 3}}{8}\\ = \frac{{ - 880}}{{216}} + \frac{{ - 81}}{{216}}\\ = \frac{{ - 961}}{{216}}\end{array}\)
\(B=\left[\frac{4}{11}\cdot\left(\frac{1}{25}\right)^0+\frac{7}{22}\cdot2\right]^{2010}-\left(\frac{1}{2^2}:\frac{8^2}{4^4}\right)^{2009}\)
\(B=\left[\frac{4}{11}\cdot1+\frac{7}{22}\cdot2\right]^{2010}-\left(\frac{1}{2^2}:\frac{\left(2^3\right)^2}{\left(2^2\right)^4}\right)^{2009}\)
\(B=\left[\frac{4}{11}+\frac{7}{11}\right]^{2010}-\left(\frac{1}{2^2}:\frac{2^6}{2^8}\right)^{2009}\)
\(B=1^{2010}-\left(\frac{1}{2^2}\cdot\frac{2^8}{2^6}\right)^{2009}\)
\(B=1-1^{2009}=1-1=0\)
\(\frac{7}{22}:\frac{3}{11}+\frac{7}{22}:\frac{4}{11}\)
\(=\frac{7}{22}:\left(\frac{3}{11}+\frac{4}{11}\right)\)
\(=\frac{7}{22}:\frac{7}{11}\)
\(=\frac{1}{2}\)
ti ck nha
\(\frac{7}{22}\) : (\(\frac{3}{11}\) + \(\frac{4}{11}\) )
\(\frac{7}{22}\) : \(\frac{7}{11}\) =\(\frac{7}{22}\) x \(\frac{11}{7}\) = 2