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a) \(\frac{9}{20}\) c) \(\frac{-55}{4}\)
b) \(\frac{116}{75}\) d) \(\frac{-76}{45}\)
đúng hết đấy nhé mình tính kĩ lắm ko sai đâu
chúc may mắn
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a. Vì \(\left|x-y-5\right|\ge0\forall x;y;2019\left|y-3\right|^{2020}\ge0\forall y\)
\(\Rightarrow\left|x-y-5\right|+2019\left|y-3\right|^{2020}\ge0\)
Dấu "=" xảy ra \(\Leftrightarrow\orbr{\begin{cases}\left|x-y-5\right|=0\\2019\left|y-3\right|^{2020}=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x-y-5=0\\y-3=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x-y=5\\y=3\end{cases}}\)
b. \(2\left(x-5\right)^4\ge0\forall x;5\left|2y-7\right|^5\ge0\forall y\)
\(\Rightarrow2\left(x-5\right)^4+5\left|2y-7\right|^5\ge0\)
Dấu "=" xảy ra \(\Leftrightarrow\orbr{\begin{cases}2\left(x-5\right)^4=0\\5\left|2y-7\right|^5=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x-5=0\\2y-7=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=5\\y=\frac{7}{2}\end{cases}}\)
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g)=>x+1/2=0
x=0-1/2
x=-1/2
hoặc 2/3-2x=0
2x=2/3-0
2x=2/3
x=2/3:2
x=1/3
nhìn @_@ hoa cả mắt đăng từng bài thôi bạn
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A . \(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)
\(\frac{2}{5}+x=\frac{11}{12}-\frac{2}{3}=\frac{1}{4}\)
\(x=\frac{1}{4}-\frac{2}{5}=\frac{-3}{20}\)
B . \(2.x.\left(x-\frac{1}{7}\right)=0\)
\(\Rightarrow x.\left(x-\frac{1}{7}\right)=0\)
\(\Rightarrow x=0\)
C .\(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)
\(\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}\)
\(\frac{1}{4}:x=\frac{-7}{20}\)
\(x=\frac{1}{4}:\frac{-7}{20}\)
\(x=\frac{-5}{7}\)
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a
\(5\frac{4}{7}:x+=13\)
\(\frac{39}{7}:x=13\)
\(x=\frac{39}{7}:13\)
\(x=\frac{3}{7}\)
\(\frac{4}{7}x=\frac{9}{8}-0,125\)
\(\frac{4}{7}x=1\)
\(x=1:\frac{4}{7}\)
\(x=\frac{7}{4}=1\frac{3}{4}\)
\(\frac{4}{5}x-3x^2=0\)
\(\Leftrightarrow x\left(\frac{4}{5}-3x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\\frac{4}{5}-3x=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\3x=\frac{4}{5}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{4}{5}:3\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{4}{5}.\frac{1}{3}=\frac{4}{15}\end{cases}}\)
Vậy x = 0 hoặc\(x=\frac{4}{15}\)
Linz
ta có :
vì 4/5*x-3*x^2=0 nên
4/5*x=3*x^2
ta có :4/5*x=3*x*x
4/5=3*x
3x=4/5
x=4/5:3
x=4/15
ok nhé