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\(B=\)\(\frac{3+33+333+3333+33333}{4+44+444+4444+44444}\)
\(B=\frac{3.1+3.11+3.111+3.1111+3.11111}{4.1+4.11+4.111+4.1111+4.11111}\)
\(B=\frac{3.\left(1+11+111+1111+11111\right)}{4.\left(1+11+111+1111+11111\right)}\)
\(B=\frac{3}{4}\)
\(A=\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}\)
\(A.2=\left(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}\right).2\)
\(A.2=\frac{2}{3}+\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)
=>\(A.2-A=\left(\frac{2}{3}+\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\right)-\left(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}\right)\)
\(A=\frac{2}{3}-\frac{1}{192}\)
\(A=\frac{127}{192}\)
\(\frac{1995}{1997}.\frac{1990}{1993}.\frac{1997}{1994}.\frac{1993}{1995}.\frac{997}{995}\)
Đặt \(C=\frac{1995}{1997}.\frac{1990}{1993}.\frac{1997}{1994}.\frac{1993}{1995}.\frac{997}{995}\)
\(C=\frac{1995.1990.1997.1993.997}{1997.1993.1994.1995.995}\)
\(C=\frac{1990.997}{1994.995}\)
\(C=\frac{995.2+997}{997.2+995}=1\)
\(B=\frac{3+33+333+3333+ 33333}{4+44+444+4444+44444}\)
\(\Rightarrow B=\frac{3\left(1+11+111+1111+11111\right)}{4\left(1+11+111+1111+11111\right)}=\frac{3}{4}\)
a, 6/9+5/7+1/3=2/3+5/7+1/3=5/7+1=12/7
b, 17/7+6/5-20/14=17/7+6/5-10/7=6/5+1=11/5
c,2/5x1/4+3/4x2/5=2/5x(1/4+3/4)=2/5x1=2/5
d, 6/11:4/6+5/11:2/3=6/11:2/3+5/11:2/3=(6/11+5/11):2/3=3/2
nha
#)Trả lời :
\(a,\frac{2}{3}:\frac{5}{7}.\frac{5}{7}:\frac{2}{3}+1934\)
\(=\left(\frac{2}{3}:\frac{2}{3}\right).\left(\frac{5}{7}:\frac{5}{7}\right)+1934\)
\(=1.1+1934\)
\(=1935\)
#~Will~be~Pens~#
a) \(\frac{24}{x}\div\frac{8}{3}=\frac{3}{5}\)
\(\frac{24}{x}\cdot\frac{3}{8}=\frac{3}{5}\)
\(\frac{24}{x}=\frac{3}{5}\div\frac{3}{8}\)
\(\frac{24}{x}=\frac{24}{15}\)
Vậy x = 15
b) Tương tự
Câu 1\(\frac{9}{8}.\frac{9}{3}=\frac{81}{24}\)
Câu 2 \(\frac{19}{5}+\frac{9}{5}=\frac{28}{5}\)
Câu 3 \(\frac{31}{7}:\frac{22}{5}=\frac{31.5}{7.22}=\frac{155}{154}\)
Câu 4 \(\frac{12}{1}-\frac{31}{5}=\frac{60}{5}-\frac{31}{5}=\frac{29}{5}\)
Ta có : \(\frac{1995.1996-1997}{1995.1994+1993}\times\frac{6}{5}\)
\(=\frac{1995.\left(1994+2\right)-1997}{1995.1994+1993}\times\frac{6}{5}\)
\(=\frac{1995.1994+1995.2-1997}{1995.1994+1993}\times\frac{6}{5}\)
\(=\frac{1995.1994+3990-1997}{1995.1994+1993}\times\frac{6}{5}\)
\(=\frac{1996.1994+1993}{1995.1994+1993}\times\frac{6}{5}\)
\(=1\times\frac{6}{5}\)
\(=\frac{6}{5}\)
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