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HM
1
BQ
8 tháng 8 2017
71 + 52,5 x 4 = \(\dfrac{x+140}{x}\)+ 210
71 + 210 = (x + 140) : x + 210
71 = x : x + 140 : x (cùng bỏ trừ đi 210)
71 = 1 + 140 : x
71 - 1 = 140 : x
70 = 140 : x
140 : 70 = x
2 = x
6 tháng 8 2016
71 + 65 x 4 = \(\frac{x+140}{x+260}\)
71 + 260 = \(\frac{x+140}{x+260}\)
331 = \(\frac{x+140}{x+260}\)
\(\Rightarrow x+140=331\left(x+260\right)\)
\(\Rightarrow x+140=331x+86060\)
\(\Rightarrow140-86060=331x-x\)
\(\Rightarrow330x=85920\)
\(\Rightarrow x=\frac{2864}{11}\)
25 tháng 7 2017
a)(x.0,25+1999)x2000=(53+1999)x2000
(x.0,25+1999)=53+1999
x.0,25=53
x=53x4
x=210
30 tháng 3 2018
a)(x.0,25+1999)x2000=(53+1999)x2000
(x.0,25+1999)=53+1999
x.0,25=53
x=53x4
x=210
k mik đi
27 tháng 3 2017
b) \(-2\dfrac{2}{3}:x=1\dfrac{7}{9}:0.8\\ -\dfrac{8}{3}:x=\dfrac{16}{9}:\dfrac{4}{5}\\ -\dfrac{8}{3}:x=\dfrac{16}{9}.\dfrac{5}{4}\\ -\dfrac{8}{3}:x=\dfrac{20}{9}\\ x=-\dfrac{8}{3}:\dfrac{20}{9}\\ x=-\dfrac{8}{3}.\dfrac{9}{20}\\ x=-\dfrac{6}{5}\)
27 tháng 3 2017
\(2\dfrac{2}{3}x+3\dfrac{3}{4}x=\dfrac{385}{24}\)
\(\dfrac{8}{3}x+\dfrac{15}{4}x=\dfrac{385}{24}\)
\(x\left(\dfrac{8}{3}+\dfrac{15}{4}\right)=\dfrac{385}{24}\)
\(x\left(\dfrac{32}{12}+\dfrac{45}{12}\right)=\dfrac{385}{24}\)
\(x\left(\dfrac{77}{12}\right)=\dfrac{385}{24}\)
\(x=\dfrac{385}{24}:\dfrac{77}{12}\)
\(x=\dfrac{385}{24}.\dfrac{12}{77}\)
<Bạn tự viết phép tính nha>
\(x=\dfrac{5}{2}\)
Vậy \(x=\dfrac{5}{2}\)
Chúc bn hk tốt!!
HT
16 tháng 7 2015
(x+1)+(x+4)+(x+7)+....+(x+28)=155
x+x+x+...+x+(1+4+7+....+28) = 155
10x + 145 = 155
=> 10x = 155 - 145
=> 10x = 10
=> x = 10:10
=> x =1
20 tháng 9 2016
a) (x + 1 ) + ( x + 4 ) + ( x + 7 ) + ... + ( x + 28 ) = 155
( x + x + x + ... + x ) + ( 1 + 4 + 7 + ... + 28 ) = 155
10x + 145 = 145
10x = 155 - 145
10x = 10
=> x = 10 : 10
=> x = 1
26 tháng 8 2021
a) 3/x-7 = 27/135
3/x-7 = 3/15
x - 7 = 15
x = 15 + 7
x = 22
GW
26 tháng 8 2021
a) \(\frac{3}{x-7}=\frac{27}{135}\)
\(\Rightarrow\)\(\left(x-7\right).27=3.135\)
\(\Rightarrow\)\(\left(x-7\right).27=405\)
\(\Rightarrow\)\(x-7=15\)
\(\Rightarrow\)\(x=22\)
Vậy \(x=22\)
b ) \(71+65.4=\frac{x+140}{x}+260\)
\(71+260=\frac{x+140}{x}+260\)
\(331=\frac{x+140}{x}+260\)
\(331-260=\frac{x+140}{x}\)
\(71=\frac{x+140}{x}\)
\(71=\frac{x}{x}+\frac{140}{x}\)
\(71=1+\frac{140}{x}\)
\(70=\frac{140}{x}\)
\(x=140\div70\)
\(x=20\)
Vậy \(x=20\)
#TQY
16 tháng 4 2017
Câu 1:
Ta có: \(\dfrac{x-4}{y-3}=\dfrac{4}{3}\)
=> \(3.\left(x-4\right)=4.\left(y-3\right)\)
=>\(3x-12=4y-12\)
=>\(3x=4y\) (1)
Ta có: \(x-y=5\)
=> \(y=y+5\) Thay vào (1) ta có:
\(3.\left(y+5\right)=4.\)y
=>\(3y+15=4y\)
=> \(15=4y-3y\)
=> 15 = y
=> y =15
ta có: x = y +5
=> x = 15 +5
=> x =20
16 tháng 4 2017
Câu 2:
\(B=\dfrac{10}{56}+\dfrac{10}{140}+\dfrac{10}{260}+...+\dfrac{10}{1400}\)
\(B=\dfrac{5}{28}+\dfrac{6}{70}+\dfrac{5}{130}+...+\dfrac{5}{700}\)
\(B=\dfrac{5}{4.7}+\dfrac{5}{7.10}+\dfrac{5}{10.13}+...+\dfrac{5}{25.28}\)
\(B=5,\left(\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}+...+\dfrac{1}{25}-\dfrac{1}{28}\right)\)
\(3B=5.\left(\dfrac{3}{4.7}+\dfrac{3}{7.10}+\dfrac{3}{10.13}+...+\dfrac{3}{25.28}\right)\)
\(3B=5.\left(\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}+...+\dfrac{1}{25}-\dfrac{1}{28}\right)\)
\(3B=5.\left(\dfrac{1}{4}-\dfrac{1}{28}\right)\)
\(3B=5.\dfrac{3}{14}\)
\(B=\dfrac{15}{14}:3=\dfrac{5}{14}\)
Câu 3:
38 - (|x+10|+13) = \(\left(-6\right)^{20}:\left(9^9.4^{10}\right)\)
=> \(38-\left(\left|x+10\right|+13\right)=\left(2.3\right)_{ }^{20}:\)\(\left[\left(3^2\right)^9.\left(2^2\right)^4\right]\)
=>\(38-\left(\left|x+10\right|+13\right)=2^{20}.3^{20}:\left(3^{18}.2^{20}\right)\)
=> \(38-\left(\left|x+10\right|+13\right)=\dfrac{3^{20}.2^{20}}{3^{18}.2^{20}}\)
=> \(38-\left(\left|x+10\right|+13\right)=9\)
=> |x +10| + 13 = 38 -9
=> |x+10| +13 = 29
=> |x+10| = 29 -13
=> |x+10| = 16
\(\Rightarrow\left[{}\begin{matrix}x+10=16\\x+10=-16\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=6\\x=-26\end{matrix}\right.\)
3 tháng 4 2017
Ta có \(\dfrac{x+5}{7}=\dfrac{40}{140}\)
\(\Leftrightarrow\dfrac{x+5}{7}=\dfrac{2}{7}\\ \Leftrightarrow x+5=2\\ \Leftrightarrow x=-3\)
Tương tự : \(\dfrac{-30}{5y+5}=\dfrac{40}{140}\)
\(\Leftrightarrow\dfrac{-6}{y+1}=\dfrac{2}{7}\\ \Leftrightarrow\left(y+1\right)\cdot2=-6\cdot7\\ \Leftrightarrow2y+2=-42\)
\(\Leftrightarrow2y=-44\\ \Leftrightarrow y=-22\)
Vậy..................................
\(\dfrac{x+140}{x}.260=71+65.4\) ( ĐK : x khác 0 )
\(\Leftrightarrow\dfrac{x+140}{x}.260=331\)
\(\Leftrightarrow\dfrac{x+140}{x}=\dfrac{331}{260}\)
\(\Rightarrow260\left(x+140\right)=331x\)
\(\Leftrightarrow x\approx512,7\)
xx+140.260=71+65.4 ( ĐK : x khác 0 )
\Leftrightarrow\dfrac{x+140}{x}.260=331⇔xx+140.260=331
\Leftrightarrow\dfrac{x+140}{x}=\dfrac{331}{260}⇔xx+140=260331
\Rightarrow260\left(x+140\right)=331x⇒260(x+140)=331x
\Leftrightarrow x\approx512,7⇔x sấp sỉ = 512,7