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\(=\dfrac{3^2\left(2^2+2^3+1\right)}{-13}=\dfrac{-13\cdot3^2}{13}=-9\)
\(\frac{6^3+3.6^2+3}{-13}\)
\(=\frac{216+108+27}{-13}\)
\(=\frac{351}{-13}\)
\(=-27\)
\(\frac{6^3+3\cdot6^2+3^3}{-13}\)
\(=\frac{6^2\cdot\left(6+3\right)+3^3}{-13}\)
\(=\frac{6^2\cdot3^2+3^3}{-13}\)
\(=\frac{3^3\cdot\left(6^2+3\right)}{-13}\)
\(=\frac{3^3\cdot39}{-13}\)
\(=-3^3=-27\)
\(\frac{6^3+3.6^2+3^2}{-13}\)
\(=\frac{\left(2.3\right)^3+3.\left(2.3\right)^2+3^2}{-13}\)
\(=\frac{2^3.3^3+\left(3.3^2\right).2+3^2}{-13}\)
\(=\frac{3^2.\left(2^3.3+3.2+1\right)}{-13}\)
\(=\frac{3^2.31}{-13}\)
\(=\frac{9.31}{-13}\)
\(=\frac{273}{-13}\)
\(=-21\)
Bài 2:
1: =>5x+1=6/7 hoặc 5x+1=-6/7
=>5x=-1/7 hoặc 5x=-13/7
=>x=-1/35 hoặc x=-13/35
2: =>x-1=4
=>x=5
3: =>3x-1=3
=>3x=4
=>x=4/3
4: \(\Leftrightarrow\dfrac{5}{x+3}=\dfrac{-5}{6}+\dfrac{1}{2}=\dfrac{-5+3}{6}=\dfrac{-2}{6}=\dfrac{-1}{3}\)
=>x+3=-15
=>x=-18
7: \(\Leftrightarrow2^{2x+1}+2^{2x+6}=264\)
=>2^2x+1*(1+2^5)=264
=>2^2x+1=8
=>2x+1=3
=>x=1
9: =>x^4=8x
=>x^4-8x=0
=>x=2
\(\dfrac{6^3+3.6^2+3^3}{-13}\)=\(\dfrac{3^3.2^3+3.2^2.3^2+3^3}{-13}\)=\(\dfrac{3^3\left(2^3+2^2+1\right)}{-13}\)
=\(\dfrac{3^3.13}{-13}\)=\(-3^3\)=\(-27\)