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a) \(\dfrac{1}{3}\)của 45 = \(45.\dfrac{1}{3}=15\)
b) \(\dfrac{2}{7}\)của \(\dfrac{63}{91}\)= \(\dfrac{63}{91}.\dfrac{2}{7}=\dfrac{18}{91}\)
c) 23% của 200 = 200 . \(\dfrac{23}{100}\)= 46
d) \(1\dfrac{2}{3}\)của \(3\dfrac{1}{4}\)= \(3\dfrac{1}{4}.1\dfrac{2}{3}=\dfrac{65}{12}\)
a) Ta có:
\(\frac{232323}{999999}=\frac{23.10101}{99.10101}=\frac{23}{99}\)
Vì : \(\frac{23}{99}=\frac{23}{99}\\ =>\frac{23}{99}=\frac{232323}{999999}\)
b) \(-\frac{63}{84}=-\frac{3}{4}\\ \frac{65}{-91}=-\frac{5}{7}\)
Vì: \(-\frac{3}{4}< -\frac{5}{7}\\ =>-\frac{63}{84}< \frac{65}{-91}\)
c) Ta có: \(\frac{111}{115}=1-\frac{4}{115}\\ \frac{555}{559}=1-\frac{4}{559}\)
Vì: \(\frac{4}{115}>\frac{4}{559}\\ =>1-\frac{4}{115}< 1-\frac{4}{559}\\ =>\frac{111}{115}< \frac{555}{559}\)
a) \(\dfrac{23}{99}\) và \(\dfrac{232323}{999999}\)
* Giữ nguyên \(\dfrac{23}{99}\).
* Rút gọn \(\dfrac{232323}{999999}=\dfrac{23}{99}\).
Vì \(\dfrac{23}{99}=\dfrac{23}{99}\) nên \(\dfrac{23}{99}=\dfrac{232323}{999999}\)
Vậy \(\dfrac{23}{99}=\dfrac{232323}{999999}\).
b) \(\dfrac{-63}{84}\) và \(\dfrac{65}{-91}\)
\(\circledast\) Rút gọn:
\(\dfrac{-63}{84}=\dfrac{-3}{4}\) ; \(\dfrac{65}{-91}=\dfrac{-5}{7}\)
\(\circledast\) Quy đồng:
Mẫu chung: 28
\(\dfrac{-3}{4}=\dfrac{-3.7}{4\cdot7}=\dfrac{-21}{28}\)
\(\dfrac{-5}{7}=\dfrac{-5\cdot4}{7\cdot4}=\dfrac{-20}{28}\)
Vì \(\dfrac{-21}{28}< \dfrac{-20}{28}\) nên \(\dfrac{-63}{84}< \dfrac{65}{-91}\).
Vậy \(\dfrac{-63}{84}< \dfrac{65}{-91}\).
c) \(\dfrac{111}{115}\) và \(\dfrac{555}{559}\)
\(\dfrac{111}{115}=1-\dfrac{4}{115}\) ; \(\dfrac{555}{559}=1-\dfrac{4}{559}\)
Vì \(\dfrac{4}{115}>\dfrac{4}{559}\)
\(\Rightarrow\) \(1-\dfrac{4}{115}< 1-\dfrac{4}{559}\)
\(\Rightarrow\) \(\dfrac{111}{115}< \dfrac{555}{559}\)
Vậy \(\dfrac{111}{115}< \dfrac{555}{559}\).
a) \(\dfrac{7}{13}\)\(\times\)\(\dfrac{7}{15}\)-\(\dfrac{5}{12}\)\(\times\)\(\dfrac{21}{39}+\dfrac{49}{91}\)\(\times\)\(\dfrac{8}{15}\)
= \(\dfrac{7}{13}\)\(\times\)\(\dfrac{7}{15}\)-\(\dfrac{5}{12}\times\dfrac{7}{13}+\dfrac{7}{13}\times\dfrac{8}{15}\)
= \(\dfrac{7}{13}\left(\dfrac{7}{15}-\dfrac{5}{12}+\dfrac{8}{15}\right)\)
= \(\dfrac{7}{13}\times\dfrac{7}{12}\)
= \(\dfrac{49}{156}\)
b) \(\left(\dfrac{12}{199}+\dfrac{23}{200}-\dfrac{34}{201}\right)\times\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)
= \(\left(\dfrac{12}{199}+\dfrac{23}{200}-\dfrac{34}{201}\right)\times0\)
= 0
\(VT=91\left(\dfrac{1}{1\cdot4}+\dfrac{1}{4\cdot7}+...+\dfrac{1}{88\cdot91}\right)\)
\(=\dfrac{91}{3}\cdot\left(\dfrac{3}{1\cdot4}+\dfrac{3}{4\cdot7}+...+\dfrac{3}{88\cdot91}\right)\)
\(=\dfrac{91}{3}\cdot\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{88}-\dfrac{1}{91}\right)\)
\(=\dfrac{91}{3}\cdot\dfrac{90}{91}=30\)
Ừk
7.
\(G=\dfrac{2}{15}+\dfrac{2}{35}+\dfrac{2}{63}+\dfrac{2}{99}+\dfrac{2}{143}\\ =\dfrac{2}{3\cdot5}+\dfrac{2}{5\cdot7}+\dfrac{2}{7\cdot9}+\dfrac{2}{9\cdot11}+\dfrac{2}{11\cdot13}\\ =\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{13}\\ =\dfrac{1}{3}-\dfrac{1}{13}\\ =\dfrac{13}{39}-\dfrac{3}{39}\\ =\dfrac{10}{39}\)
8.
\(H=\dfrac{1}{7}+\dfrac{1}{91}+\dfrac{1}{247}+\dfrac{1}{475}+\dfrac{1}{755}+\dfrac{1}{1147}\\ =\dfrac{1}{1\cdot7}+\dfrac{1}{7\cdot13}+\dfrac{1}{13\cdot19}+\dfrac{1}{19\cdot25}+\dfrac{1}{25\cdot31}+\dfrac{1}{31\cdot37}\\ =\dfrac{1}{6}\cdot\left(\dfrac{6}{1\cdot7}+\dfrac{6}{7\cdot13}+\dfrac{6}{13\cdot19}+\dfrac{6}{19\cdot25}+\dfrac{6}{25\cdot31}+\dfrac{6}{31\cdot37}\right)\\ =\dfrac{1}{6}\cdot\left(\dfrac{1}{1}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{19}+\dfrac{1}{19}-\dfrac{1}{25}+\dfrac{1}{25}-\dfrac{1}{31}+\dfrac{1}{31}-\dfrac{1}{37}\right)\\ =\dfrac{1}{6}\cdot\left(1-\dfrac{1}{37}\right)\\ =\dfrac{1}{6}\cdot\dfrac{36}{37}\\ =\dfrac{6}{37}\)
b: \(A=5\left(\dfrac{5}{1\cdot6}+\dfrac{5}{6\cdot11}+...+\dfrac{5}{26\cdot31}\right)\)
\(=5\left(1-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{11}+...+\dfrac{1}{26}-\dfrac{1}{31}\right)\)
\(=5\cdot\dfrac{30}{31}=\dfrac{150}{31}\)
c: \(C=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{16}\)
=1-1/16=15/16
Bài 2.
A = -3/5 + ( -2/5 + 2 )
A = -3/5 + ( -2/5 + 10/5 )
A = -3/5 + 8/5
A = 5/5
A = 1
--------------------------------------------------------
B = 3/7 + ( -1/5 + -3/7 )
B = 3/7 + ( -7/35 + -15/35 )
B = 3/7 + ( -22/35 )
B = 15/35 + ( -22/35 )
B = -1/5
-----------------------------------------------------
C = ( -5/24 + 0,75 + 7/12 ) : ( -2 . 1/8 )
C = ( -5/24 + 3/4 + 7/12 ) : ( -1/4 )
C = 9/8 : ( -1/4 )
C = 9/8 . ( -4 )
C = -9/2
Bài 3 .
a) 4/7 - x = 1/2 . x + 2/7
<=> -x - x = 1/2 - 4/7 + 2/7
<=> -2x = 3/14
<=> x = 3/14 . ( -1/2 )
<=> x = -3/28
Vậy x = -3/28
b) x : 3 1/5 = 1 1/2
<=> x : 16/5 = 3/2
<=> x = 3/2 . 16/5
<=> x = 24/5
Vậy x = 24/5
c) x . 3/4 = -1 5/8
<=> x . 3/4 = -13/8
<=> x = -13/8 . 4/3
<=> x = -13/6
Vậy x = -13/6
2/7 của 63/91
=63/91. 2/7
=18/91
chú thích : / là phần nha