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\(=\frac{3}{4}\left(\frac{8}{9}+\frac{2}{3}\right)=\frac{3}{4}\left(\frac{8}{9}+\frac{6}{9}\right)=\frac{3}{4}x\frac{14}{9}=\frac{7}{6}..\)
mình nhầm chỗ \(\frac{8}{9}\)và \(\frac{3}{4}\)có một dấu cộng
Bài 1:
a) \(\frac{3}{4}×\frac{4}{7}=\frac{3×4}{4×7}=\frac{3}{7}\)
\(\frac{12}{35}:\frac{3}{5}=\frac{12}{35}×\frac{5}{3}=\frac{12×5}{35×3}=\frac{4.}{7}\)
\(\frac{4}{7}×\frac{3}{5}=\frac{4×3}{7×5}=\frac{12}{35}\)
b) \(\frac{13}{11}×2=\frac{13×2}{11}=\frac{26}{11}\)
\(\frac{26}{11}:\frac{13}{11}=\frac{26}{11}×\frac{11}{13}=\frac{26×11}{11×13}=\frac{2×1}{1×1}=\frac{2}{1}=2\)
\(\frac{26}{11}:2=\frac{26}{11}×\frac{1}{2}=\frac{26×1}{11×2}=\frac{13×1}{11×1}=\frac{13}{11}\)
\(2×\frac{13}{11}=\frac{2×13}{11}=\frac{26}{11}\)
k giúp mik ✅
Bài 2:
a) \(\frac{4}{7}×\:x\:=\frac{1}{3}\)
\(\Rightarrow\)x = \(\frac{1}{3}-\frac{4}{7}\)
\(\Rightarrow\)x = \(\frac{7}{21}-\frac{4}{21}\)
\(\Rightarrow\)x = \(\frac{3}{21}=\frac{1}{7}\)
b) x : \(\frac{2}{5}=\frac{2}{9}\)
\(\Rightarrow\)x = \(\frac{2}{9}×\frac{2}{5}\)
\(\Rightarrow\)x = \(\frac{4}{45}\)
1.
a) \(\frac{16}{24}-\frac{1}{3}=\frac{16}{24}-\frac{8}{24}=\)\(\frac{8}{24}=\frac{1}{3}\)
b) \(\frac{4}{5}-\frac{12}{60}=\frac{48}{60}-\frac{12}{60}=\frac{36}{60}=\frac{9}{15}\)
3.
a)\(\frac{17}{6}-\frac{2}{6}=\frac{17-2}{6}=\frac{15}{6}\)
b) \(\frac{16}{15}-\frac{11}{15}=\frac{16-11}{15}=\frac{5}{15}=\frac{1}{3}\)
c) \(\frac{19}{12}-\frac{13}{12}=\frac{19-13}{12}=\frac{6}{12}=\frac{1}{2}\)
\(3+\frac{2}{5}-\frac{3}{4}\times\frac{4}{5}\)
\(=3+\frac{2}{5}-\frac{3}{4}\)
\(=\frac{3\times20+2\times4-3\times5}{20}\)
\(=\frac{60+8-15}{20}\)
\(=\frac{68-15}{20}\)
\(=\frac{53}{20}\)
\(5-\frac{7}{9}+\frac{2}{3}-\frac{5}{6}:\frac{4}{9}\)
\(=5-\frac{7}{9}+\frac{2}{3}-\frac{45}{24}\)
\(=\frac{5\times72-7\times8+2\times24-45\times3}{72}\)
\(=\frac{360-56+48-135}{72}\)
\(=\frac{217}{72}\)
a) 12 882
4719
975
8656
b) 8274
5953
16 648
4604 (dư 2)