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a. -20+5=-15
b. 7
c. 35 + (-4)= 31
d. -129-37+29-63= -100-100 = -200
e. 217 -315-117+215 =100-100=0
f. 15:(-3)+24:2 = -5 + 12 = 7
g. (-5).(-7)-3.(14)= 35 - 42 = -7
H. (-15)x(-129+29) = -15 x -100 =1500
i. 13 x (-125+25) =13 x -100 = -1300
k. 37(-135+35) = 37 x -100 = -3700
6A=5.7.6+7.9.6+9.11.6+11.13.6+13.15.6+...+99.101.6
6A=5.7.(9-3)+7.9.(11-5)+9.11.(13-7)+11.13.(15-9)+13.15.(17-11)+...+99.101.(103-97)
6A=-3.5.7+5.7.9-5.7.9+7.9.11-7.9.11+9.11.13-9.11.13+11.13.15-11.13.15+13.15.17-...-97.99.101+99.101.103
6A=99.101.103-3.5.7 => A=(99.101.103-3.5.7)/6
a, \(\dfrac{5}{9}.\dfrac{10}{11}+\dfrac{5}{9}.\dfrac{14}{11}-\dfrac{5}{9}.\dfrac{15}{11}=\dfrac{5}{9}.\left(\dfrac{10}{11}+\dfrac{14}{11}-\dfrac{15}{11}\right)=\dfrac{5}{9}.\dfrac{9}{11}=\dfrac{5}{11}\)
b, \(\dfrac{6}{7}.\dfrac{8}{13}+\dfrac{6}{13}.\dfrac{9}{7}-\dfrac{3}{13}.\dfrac{6}{7}\)\(=\dfrac{6}{7}.\left(\dfrac{8}{13}-\dfrac{3}{13}\right)+\dfrac{6}{13}.\dfrac{9}{7}=\dfrac{6}{7}.\dfrac{5}{13}+\dfrac{54}{91}=\dfrac{30}{91}+\dfrac{54}{91}=\dfrac{84}{91}=\dfrac{12}{13}\)
Bạn ơi, gõ latex cho dễ nhìn nhé!
\(\dfrac{5}{11}\cdot\dfrac{3}{17}+\dfrac{5}{11}\cdot\dfrac{8}{17}=\dfrac{5}{11}\cdot\left(\dfrac{3}{17}+\dfrac{8}{17}\right)=\dfrac{5}{11}\cdot\dfrac{11}{17}=\dfrac{5}{17}\)
c: \(=\dfrac{4}{9}\left(\dfrac{5}{7}+\dfrac{2}{5}+\dfrac{2}{7}-\dfrac{7}{5}\right)=\dfrac{4}{9}\cdot\left(1-1\right)=0\)
d: \(=\dfrac{4-3-1}{12}\cdot\left(\dfrac{67}{111}+\dfrac{2}{33}-\dfrac{15}{117}\right)=0\cdot\left(\dfrac{67}{111}+\dfrac{2}{33}-\dfrac{15}{117}\right)=0\)
-5/9 - ( -5/12 ) =-5/9+5/12=-20/36+15/36=-5/36
-1/16 - 1/15=-15/240-16/240=-31/240
11/36 - ( -7/24 )=11/36+7/24=22/72+21/72 =43/72
\(-\frac{5}{9}-\left(-\frac{5}{12}\right)=-\frac{60}{108}-\left(-\frac{45}{108}\right)=-\frac{15}{108}=-\frac{5}{36}.\)
\(\frac{-1}{6}-\frac{1}{15}=\frac{-5}{30}-\frac{2}{30}=\frac{-7}{30}\)
\(\frac{11}{36}-\left(-\frac{7}{24}\right)=\frac{22}{72}-\left(-\frac{21}{72}\right)=\frac{43}{72}\)
\(D=\dfrac{5}{7}\cdot\dfrac{40}{11}-\dfrac{5}{11}-\dfrac{117}{7}\)
\(=\dfrac{5}{11}\left(\dfrac{40}{7}-5\right)-\dfrac{117}{7}\)
\(=\dfrac{5}{11}\cdot\dfrac{5}{7}-\dfrac{117}{7}=\dfrac{25}{77}-\dfrac{117}{7}=-\dfrac{1262}{77}\)