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\(a.2^{x-1}=16\)
\(2^{x-1}=2^4\)
\(\Rightarrow x-1=4\)
\(x=5\)
\(b.\left(x-1\right)^2=5^2\)
\(\Rightarrow\orbr{\begin{cases}x-1=5\\x-1=-5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=6\\x=-4\end{cases}}\)
\(c.\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
\(\Rightarrow x-\frac{1}{2}=\frac{1}{3}\)
\(x=\frac{5}{6}\)
1: \(=\dfrac{3}{4}+\dfrac{5}{4}\cdot\dfrac{8}{3}-\dfrac{1}{4}\cdot\dfrac{5}{6}=\dfrac{3}{4}+\dfrac{10}{3}-\dfrac{5}{24}\)
\(=\dfrac{18}{24}+\dfrac{80}{24}-\dfrac{5}{24}=\dfrac{93}{24}=\dfrac{31}{8}\)
2: \(=\left(7+\dfrac{23}{27}-\dfrac{23}{27}\right)+\left(\dfrac{11}{25}+\dfrac{14}{25}\right)+3.25\)
\(=7+1+3.25=8+3.25=11.25\)
3: \(=\left(\dfrac{1}{9}\cdot9\right)^{2005}-4^2=1-16=-15\)
4: \(=2\cdot\dfrac{9}{4}-\dfrac{7}{2}=\dfrac{9}{2}-\dfrac{7}{2}=1\)
5: \(=\dfrac{15}{2}\cdot\dfrac{-3}{5}+\dfrac{5}{2}\cdot\dfrac{-3}{5}=\dfrac{-3}{5}\cdot\left(\dfrac{15}{2}+\dfrac{5}{2}\right)=\dfrac{-3}{5}\cdot10=-6\)
6: \(=\left(\dfrac{6}{10}+\dfrac{5}{10}\right)^2=\left(\dfrac{11}{10}\right)^2=\dfrac{121}{100}\)
7: \(=\dfrac{1}{2}\cdot\dfrac{-7}{2}=\dfrac{-7}{4}\)
\(\left(x-1\right)^3=27\)
\(\Leftrightarrow\left(x-1\right)^3=3^3\)
\(\Leftrightarrow x-1=3\)
\(\Leftrightarrow x=4\)
\(x^2+x=0\)
\(\Leftrightarrow x\left(x+1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-1\end{cases}}\)
Vậy x = 0 hoặc x = -1
\(\left(2x+1\right)^2=25\)
\(\Leftrightarrow\left(2x+1\right)^2=\left(\pm5\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}2x+1=5\\2x+1=-5\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-3\end{cases}}\)
Vậy x = 2 hoặc x = -3
\(\left(2x-3\right)^2=36\)
\(\Leftrightarrow\left(2x-3\right)^2=\left(\pm6\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}2x-3=6\\2x-3=-6\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=4,5\\x=-1,5\end{cases}}\)
Vậy x = 4,5 hoặc x = -1,5
a, (x - 2)2 = 1
(x - 2)2 = -12
=> x - 2 = -1
x = -1 + 2
x = -1
b, (2x - 1)3 = -27
(2x - 1)3 = -33
=> 2x - 1 = -3
2x = -3 + 1
2x = -2
x = -2 : 2
x = -1
a) (x-2)^2 = 1 = 1^2 = (-1)^2
=> x-2 = 1 => x = 3
x - 2 = -1 => x = 1
.KL:..
b) (2x-1)^3 = -27 = (-3)^3
=> 2x-1 = -3 => 2x = -2 => x = -1
c)16/2^n = 1
2^4 : 2^n = 1
24-n = 1 = 20
=> 4-n = 0 => n = 4
c) (x-1/2)^3 = 1/27 = 1/3^3
=>x-1/2 = 1/3
x = 5/6
d) (x+1/2)^2 = 4/25 = (2/5)^2 = (-2/5)^2
...
rùi bn tự lm như phần a nha
e) (x-1)x+2 = (x-1)x+6
=> (x-1)x+2 - (x-1)x+6 = 0
(x-1)x+2.[1-(x-1)4 ] = 0
=> (x-1)x+2 = 0 => x-1 = 0 => x = 1
1-(x-1)4 = 0 => (x-1)^4 = 1 => x -1 = 1 => x = 2
x -1 = -1 => x = 0
KL:...
f) (x-2)2 + (y-3)2 = 0
=> (x-2)^2 = 0 => x - 2=0 => x = 2
(y-3)^2=0 => y-3 = 0 => y =3
g) 5(x-2).(x+3) = 1 = 50
=> (x-2).(x+3) = 0
=> x-2 = 0 => x = 2
x+3 = 0 => x = -3
KL:...
Đặt \(B=4^{2004}+4^{2003}+...+4^2+4+1\)
\(\Leftrightarrow4B=4^{2005}+4^{2004}+...+4^3+4^2+4\)
\(\Leftrightarrow B=\dfrac{4^{2005}-1}{3}\)
\(A=75\cdot\dfrac{4^{2005}-1}{3}+25\)
\(=25\left(4^{2005}-1+1\right)=100\cdot4^{2004}⋮100\)