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a) 76 + 75 - 74
= 74.(72 + 7 - 1)
= 74.(49 + 7 - 1)
= 74.55
= 74.5.11 \(⋮11\left(đpcm\right)\)
b) 109 + 108 + 107
= 107.(102 + 10 + 1)
= 57.27.(100 + 10 + 1)
= 57.26.2.111
= 57.26.222 \(⋮222\left(đpcm\right)\)

a, \(10^9+10^8+10^7⋮222\)
Ta có:\(10^9+10^8+10^7=10^7.\left(10^2+10+1\right)\)
\(=10^7.111=5^7.2^7.111=5^7.2^6.2.111=5^7.2^6.222\)
Vì 222\(⋮222\Rightarrow5^7.2^6.222⋮222\)
Vậy \(10^9+10^8+10^7⋮222\)
b) 817 - 279 - 913 ⋮ 45
\(\)Ta có: \(81^7-27^9-9^{13}=\left(3^4\right)^7-\left(3^3\right)^9-\left(3^2\right)^{13}\)
\(=3^{28}-3^{27}-3^{26}=3^{26}.\left(3^2-3-1\right)\)
\(=3^{26}.5=3^{24}.3^2.5=3^{24}.45\)
Vì \(45⋮45\Rightarrow3^{24}.45⋮45\)
Vậy \(81^7-27^9-9^{13}⋮45\)
CHÚC BẠN HỌC TỐT!!

a) \(7^6+7^5-7^4=7^4.7^2+7^4.7+7^4.1\)
\(=7^4.\left(7^2+7-1\right)\)
\(=7^4.55\)
Mà \(55⋮11\Rightarrow7^4.55⋮11\Leftrightarrow7^6+7^5-7^4⋮11\left(đpcm\right).\)
b) \(10^9+10^8+10^7=10^6.10^3+10^6.10^2+10^6.10\)
\(=10^6.\left(10^3+10^2+10\right)\)
\(=10^6.1110\)
Mà \(1110⋮222\Rightarrow10^6.110⋮222\Leftrightarrow10^9+10^8+10^7⋮222\left(đpcm\right).\)
c) \(81^7-27^9-9^{13}=\left(3^4\right)^7-\left(3^3\right)^9-\left(3^2\right)^{13}\)
\(=3^{28}-3^{27}-3^{26}\)
\(=3^{26}.3^2+3^{26}.3+3^{26}.1\)
\(=3^{26}.\left(3^2+3+1\right)\)
\(=3^{24}.3^2.5\)
\(=3^{24}.45\)
Mà \(45⋮45\Rightarrow3^{24}.45⋮45\Leftrightarrow81^7-27^9-9^{13}⋮45\left(đpcm\right).\)
d) \(24^{54}.54^{24}.2^{10}=\left(8.3\right)^{54}.\left(27.2\right)^{24}.2^{10}\)
\(=\left(2^3.3\right)^{54}.\left(3^3.2\right)^{24}.2^{10}\)
\(=\left(2^3\right)^{54}.3^{54}.\left(3^3\right)^{24}.2^{24}.2^{10}\)
\(=2^{162}.3^{54}.3^{72}.2^{34}\)
\(=2^{196}.3^{126}\)
\(=2^{189}.2^7.3^{126}\)
\(=\left[\left(2^3\right)^{63}.\left(3^2\right)^{63}\right].2^7\)
\(=\left(8^{63}.9^{63}\right).2^7\)
\(=72^{63}.2^7\)
Mà \(72^{63}⋮72^{63}\Rightarrow72^{63}.2^7⋮72^{63}\Leftrightarrow24^{54}.54^{24}.2^{10}⋮72^{63}\left(đpcm\right).\)

Ta có : 1010 - 109 - 108
= 108(102 - 10 - 1)
= 108.89
Mà 108 thuộc N
Nên 108.89 chia hết cho 89
Vậy 1010 - 109 - 108 chia hết cho 89
\(10^{10}\)- \(10^9\) - \(10^8\)= \(10^8\). ( \(10^2\)- 10 - 1 )
= \(10^8\). 89 chia hết cho 89

a/ \(16^5+2^{15}=\left(2^4\right)^5+2^{15}=2^{20}+2^{15}=2^{15}.\left(2^5+1\right)=2^{15}.33\)chia hết cho 33
b/ \(10^9+10^8+10^7=10^7\left(10^2+10+1\right)=10^6.2.5.111=10^6.2.555\)chia hết cho 555

A = 710 + 79 _ 78
A = 78 . ( 72 + 7 - 1 )
A = 78 . 55
A = 78 . 5 . 11 \(⋮\)11
Ta có :
710 + 79 - 78
= 78 ( 72 + 7 - 1 )
= 78 x 55 = 78 x 5 x 11
\(\Rightarrow7^8\times5\times11⋮11\)
nhầm nha : 109+ 108 + 107 chia hết cho 555
Ta có :
109 = 1000000000
108 = 100000000
107 = 10000000
=> 109 + 10 8 + 10 7 = 1000000000 + 100000000 + 10000000 = 1110000000
=> 1110000000 : 555 = 2000000 ( không dư )
Vậy 109 + 10 8 + 10 7 chia hết cho 555
~ Hok tốt ~
P/s : Cái này mik làm bừa nha , ko biết đúng hay sai đâu