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16 tháng 1 2016

a) Vì A + B + C = \(180^0\)

=>    40+ B + C = 1800

                B + C = 180- 400

                B + C = 1400

=> Vì \(\Delta\)ABC cân tại A nên:

                B và C = 1400 : 2 = 700

16 tháng 1 2016

Tổng số đo 3 góc trong tam giác là 1800       

Suy ra tổng số đo 2 góc còn lại là 1800 -400 =1400

Vì tam giác ABC cân tại A nên số đo góc B bằng số đo góc C

Nên góc B=góc C =\(\frac{140^0}{2}=70^0\)

Vậy số đo góc C =700

số đo góc B =700

2 tháng 5 2017

bạn nào giúp mk vẽ hình đc không

27 tháng 2 2020

Xét ΔADE và ΔABC có :
AD = AB (gt)

góc DAE =góc BAC = 90 độ
AE = AC (gt)
Do đó : ΔADE = ΔABC(c − g − c)
⇒ DE = BC ( hai cạnh tương ứng )
b.
Ta có :
góc ADE =góc CDN ( hai góc đối đỉnh )
góc C= góc E
( vì ΔADE = ΔABC )
⇒ góc N = góc A 90đọ
Hay DE ⊥ BC
Vậy DE ⊥ BC

a: Xét ΔABC vuông tại A và ΔADE vuông tại A có

AB=AD

AC=AE

Do đó: ΔABC=ΔADE

b: Xét ΔAMD và ΔANB có

AM=AN

MD=NB

AD=AB

Do đó: ΔAMD=ΔANB

13 tháng 2 2016

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7 tháng 3 2017

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Vì tam giác ABC cân tại A

=> AB = AC                                      

=> Góc ABC=ACB

Mà AE = AD  (gt)

=> Tam giác AED cân tại A

Tam giác ABC có : (góc) BAC + 2ABC=180 độ   (1)

Tam giác AED có : (góc) BAC + 2AED=180 độ   (2)

(1)(2) => góc ABC=AED

Mà góc ABC và AED nằm ở vị trí đồng vị

=> ED//BC

b,

Xét tam giác AEC và ADB có:

AC = AB ( chứng minh trên )

Góc BAC chung

AE = AD ( gt )

=> Tam giác AEC=ADB (c.g.c)

=> Góc AEC = ADB ( 2 góc tương ứng)

Mà ADB = 90 độ

=> AEC = 90 độ

=> CE vuông góc với AB

22 tháng 12 2021

2ABC là sao vậy

18 tháng 1 2018

sao nhiều v bạn

24 tháng 1 2019

tự vẽ hình nhé

a, xét tam giác abd và tam giác ace có

ab=ac(gt)

góc abd=góc ace(tam giác abc cân)

bd=ce(gt)

=>tam giác abd =tam giác ace (cgc)

=>ad=ae(2 cạnh tg ứng)

b,xét tam giác bdf và tam giác ceg có

bd=ce(gt)

góc fbd=góc gce(tam giác abc cân, f thuộc ab,g thuộc ac)

=>tam giác bdf=tam giác ceg(cạnh huyện góc nhọn)

=>

Bài 1: Cho tam giác vuông ABC, góc A = 90o, phân giác BD. Kẻ BD vuông góc BC tại E. Trên tia đối của tia AB lấy điểm F sao cho AF = CE. Chứng minh rằng:a) BD là đường trung trực của AE.b) AD<DCc) Ba điểm E, D, F thẳng hàngBài 2: Cho tam giác vuông ABC, góc A = 90o , AB = 6cm, AC = 8cm.a) Tính BCb) Trung trực của BC cắt AC tại D và cắt AB tại F. Chứng minh góc DBC = góc DCBc) Trên tia đối của tia DB lấy điểm E sao cho...
Đọc tiếp

Bài 1: Cho tam giác vuông ABC, góc A = 90o, phân giác BD. Kẻ BD vuông góc BC tại E. Trên tia đối của tia AB lấy điểm F sao cho AF = CE. Chứng minh rằng:

a) BD là đường trung trực của AE.

b) AD<DC

c) Ba điểm E, D, F thẳng hàng

Bài 2: Cho tam giác vuông ABC, góc A = 90o , AB = 6cm, AC = 8cm.

a) Tính BC

b) Trung trực của BC cắt AC tại D và cắt AB tại F. Chứng minh góc DBC = góc DCB

c) Trên tia đối của tia DB lấy điểm E sao cho DE=DC. Chứng minh tam giác BCE vuông

d)Chứng minh:DF là phân giác của góc ADE và BE vuông góc CF

Bải 3: Cho tam giác đều ABC. Tia phân giác góc B cắt cạnh AC ở M. Từ A kẻ đường thẳng vuông góc với AB cắt các tia BM, BC lần lượt ở M và E. Chứng minh:

a) Tam giác ANC là tam giác cân

b) NC vuông góc BC

c) Tam giác AEC là tam giác cân

d) So sánh BC và NE

Bài 4: Cho tam giác nhọn ABC, kẻ BM vuông góc AC, CN vuông góc AB. Trên tia đối của tia BM lấy điểm D sao cho BD=AC, trên tia đối của tia CN lấy điểm E sao cho CE=AB. Chứng minh:

a) Góc ACE= góc ABD

b) Tam giác ABD = tam giác ECA

c) Tam giác AED là tam giác vuông cân

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