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1.
y=f(-1)=3*(-1)-2=-5
y=f(0)=3*0-2=-2
y=f(-2)=3*(-2)-2=-8
y=f(3)=3*3-2=7
Câu 2,3a làm tương tự,chỉ việc thay f(x) thôi.
3b
Khi y=5 =>5=5-2*x=>2*x=0=> x=0
Khi y=3=>3=5-2*x=>2*x=2=>x=1
Khi y=-1=>-1=5-2*x=>2*x=6=>x=3
f(-1)=3.1-2=3-2=1
f(0)=3.0-2=0-2=-2
f(-2)=3.(-2)-2=-6-2=-8
f(3)=3.3-2=9-2=7
\(f\left(3\right)=\left|\dfrac{3}{2}\cdot3-\dfrac{5}{2}\right|=2\)
\(f\left(-3\right)=\left|\dfrac{3}{2}\cdot\left(-3\right)-\dfrac{5}{2}\right|=7\)
\(f\left(\dfrac{1}{2}\right)=\left|\dfrac{3}{2}\cdot\dfrac{1}{2}-\dfrac{5}{2}\right|=\dfrac{7}{4}\)
\(f\left(-\dfrac{1}{2}\right)=\left|\dfrac{3}{2}\cdot\dfrac{-1}{2}-\dfrac{5}{2}\right|=\dfrac{13}{4}\)
\(f\left(2\right)=3\cdot2^3-2\cdot2^2+5=21\)
\(f\left(1\right)=3\cdot1^3-2\cdot1^2+5=3-2+5=6\)
\(f\left(-3\right)=3\cdot\left(-3\right)^3-2\cdot\left(-3\right)^2+5=3\cdot\left(-27\right)-2\cdot9+5=-94\)
Ta có
\(f\left(2\right)=3.8-2.4+5=24-3=21\)
\(f\left(1\right)=3-2+5=6\)
\(f\left(-3\right)=3.\left(-27\right)-2.9+5=-81-18+5=-94\)
\(a,f\left(1\right)=3\cdot1^2+1+1=5\\ f\left(-\dfrac{1}{3}\right)=3\cdot\left(-\dfrac{1}{3}\right)^2-\dfrac{1}{3}+1=\dfrac{1}{3}-\dfrac{1}{3}+1=1\\ f\left(\dfrac{2}{3}\right)=3\cdot\left(\dfrac{2}{3}\right)^2-\dfrac{2}{3}+1=\dfrac{4}{3}-\dfrac{2}{3}+1=\dfrac{5}{3}\\ f\left(-2\right)=3\cdot\left(-2\right)^2-2+1=11\\ f\left(-\dfrac{4}{3}\right)=3\cdot\left(-\dfrac{4}{3}\right)^2-\dfrac{4}{3}+1=\dfrac{16}{3}-\dfrac{4}{3}+1=5\)
\(b,f\left(\dfrac{2}{3}\right)=\left|2\cdot\dfrac{2}{3}-9\right|-3=\dfrac{23}{3}-3=\dfrac{14}{3}\\ f\left(-\dfrac{5}{4}\right)=\left|2\cdot\left(-\dfrac{5}{4}\right)-9\right|-3=\dfrac{23}{2}-3=\dfrac{17}{2}\\ f\left(-5\right)=\left|2\left(-5\right)-9\right|-3=19-3=16\\ f\left(4\right)=\left|2\cdot4-9\right|-3=1-3=-2\\ f\left(-\dfrac{3}{8}\right)=\left|2\cdot\left(-\dfrac{3}{8}\right)-9\right|-3=\dfrac{39}{4}-3=\dfrac{27}{4}\)
\(c,x=0\Rightarrow y=2\cdot0^2-7=-7\\ x=-3\Rightarrow y=2\cdot\left(-3\right)^2-7=11\\ x=-\dfrac{1}{2}\Rightarrow y=2\cdot\left(-\dfrac{1}{2}\right)^2-7=\dfrac{-13}{2}\\ x=\dfrac{2}{3}\Rightarrow y=2\cdot\left(\dfrac{2}{3}\right)^2-7=-\dfrac{55}{9}\)
Thay x=-3 vào hàm số f(x)=2x2+3-3+7 ta có :
y=f(x)=2.(-3)2+3-3+7 = 25
Thay x=-6 vào hàm số f(x)=2x2+3-3+7 ta có :
y=f(x)=2.(-6)2+3-3+7 = 79
Thay x=10 vào hàm số f(x)=2x2+3-3+7 ta có :
y=f(x)=2.102+3-3+7=107
f(-3)=2.(-3)2+5-3+7=27
f(-6)=2.(-6)2+5-3+7=81
f(10)=2.(10)2+5-3+7=209