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Ta có:
M = 3xyz - 3x2 + 5xy - 1
N = 5x2 + xyz - 5xy + 3 - y
M + N = 3xyz - 3x2 + 5xy - 1 + 5x2 + xyz - 5xy + 3 - y
= -3x2 + 5x2 + 3xyz + xyz + 5xy - 5xy - y - 1 + 3
= 2x2 + 4xyz - y +2.
M - N = (3xyz - 3x2 + 5xy - 1) - (5x2 + xyz - 5xy + 3 - y)
= 3xyz - 3x2 + 5xy - 1 - 5x2 - xyz + 5xy - 3 + y
= -3x2 - 5x2 + 3xyz - xyz + 5xy + 5xy + y - 1 - 3
= -8x2 + 2xyz + 10xy + y - 4.
N - M = (5x2 + xyz - 5xy + 3 - y) - (3xyz - 3x2 + 5xy - 1)
= 5x2 + xyz - 5xy + 3 - y - 3xyz + 3x2 - 5xy + 1
= 5x2 + 3x2 + xyz - 3xyz - 5xy - 5xy - y + 3 + 1
= 8x2 - 2xyz - 10xy - y + 4.
M+N
\(=3xyz-3x^2+5xy-1+5x^2+xyz-5xy+3\)
\(=2x^2+4xyz+2\)
M-N
\(=3xyz-3x^2+5xy-1-5x^2-xyz+5xy-3\)
\(=-8x^2+2xyz+10xy-4\)
Ta có:
M = 3xyz - 3x2 + 5xy - 1
N = 5x2 + xyz - 5xy + 3 - y
M + N = 3xyz - 3x2 + 5xy - 1 + 5x2 + xyz - 5xy + 3 - y
= -3x2 + 5x2 + 3xyz + xyz + 5xy - 5xy - y - 1 + 3
= 2x2 + 4xyz - y +2.
M - N = (3xyz - 3x2 + 5xy - 1) - (5x2 + xyz - 5xy + 3 - y)
= 3xyz - 3x2 + 5xy - 1 - 5x2 - xyz + 5xy - 3 + y
= -3x2 - 5x2 + 3xyz - xyz + 5xy + 5xy + y - 1 - 3
= -8x2 + 2xyz + 10xy + y - 4.
N - M = (5x2 + xyz - 5xy + 3 - y) - (3xyz - 3x2 + 5xy - 1)
= 5x2 + xyz - 5xy + 3 - y - 3xyz + 3x2 - 5xy + 1
= 5x2 + 3x2 + xyz - 3xyz - 5xy - 5xy - y + 3 + 1
= 8x2 - 2xyz - 10xy - y + 4.
M = 3xyz - 3x2 + 5xy - 1
N = 5x2 + xyz - 5xy + 3 - y
M + N = 3xyz - 3x2 + 5xy - 1 + 5x2 + xyz - 5xy + 3 - y
= -3x2 + 5x2 + 3xyz + xyz + 5xy - 5xy - y - 1 + 3
= 2x2 + 4xyz - y +2.
M - N = (3xyz - 3x2 + 5xy - 1) - (5x2 + xyz - 5xy + 3 - y)
= 3xyz - 3x2 + 5xy - 1 - 5x2 - xyz + 5xy - 3 + y
= -3x2 - 5x2 + 3xyz - xyz + 5xy + 5xy + y - 1 - 3
= -8x2 + 2xyz + 10xy + y - 4.
N - M = (5x2 + xyz - 5xy + 3 - y) - (3xyz - 3x2 + 5xy - 1)
= 5x2 + xyz - 5xy + 3 - y - 3xyz + 3x2 - 5xy + 1
= 5x2 + 3x2 + xyz - 3xyz - 5xy - 5xy - y + 3 + 1
= 8x2 - 2xyz - 10xy - y + 4.
M + N = (3xyz – 3x2 + 5xy – 1) + (5x2 + xyz – 5xy + 3 – y)
= 3xyz – 3x2 + 5xy – 1 + 5x2 + xyz – 5xy + 3 – y
= (3xyz + xyz)+( –3x2 + 5x2) + (5xy – 5xy) – y + ( – 1+3)
= 4xyz + 2x2 – y + 2
M – N = (3xyz – 3x2 + 5xy – 1) – (5x2 + xyz – 5xy + 3 – y)
= 3xyz – 3x2 + 5xy – 1 – 5x2 – xyz + 5xy – 3 + y
= (– 3x2 – 5x2) + (3xyz – xyz) + (5xy + 5xy) + y +(– 1 – 3)
= –8x2 + 2xyz + 10xy + y – 4.
N – M = (5x2 + xyz – 5xy + 3 – y) – (3xyz – 3x2 + 5xy – 1)
= 5x2 + xyz – 5xy + 3 – y – 3xyz + 3x2 – 5xy +1
= (5x2 + 3x2)+ (xyz – 3xyz)+( – 5xy – 5xy) + (3 + 1 )– y
= 8x2 – 2xyz – 10xy – y + 4.
Chú ý: Vì M – N và N – M là hai đa thức đối nhau nên
N – M = 8x2 – 2xyz – 10xy – y + 4
(Ta chỉ cần đổi dấu mỗi hạng tử của đa thức M – N là thu được N – M).
M + N = (3xyz -3x2+5xy-1)+(5x2+xyz-5xy+3 - y)
= 3xyz - 3x2 +5xy-1+5x2+xyz-5xy+3 - y
= (3xyz + xyz)+ (5x2 - 3x2)+ (5xy-5xy)+(3-1)-y
= 4xyz + 2x2 + 2 - y
M - N = (3xyz -3x2+5xy-1)-(5x2+xyz-5xy+3 - y)
= 3xyz -3x2+5xy-1- 5x2 -xyz+5xy-3 + y
= (3xyz-xyz)+(-3x2-5x2)+(5xy+5xy)+(-1-3) + y
= 2xyz + (-8x2)+10xy+(-4)+y
=2xyz - 8x2+10xy - 4 +y
theo mk là zầy!!!!
a) M+N = 3xyz - 3x2 + 5xy - 1 + 5x2 + xyz - 5xy + 3 - y
= (3xyz+xyz)+(-3x2+5x2)+(5xy-5xy)-y+(-1+3)
= 4xyz + 2x2 - y + 2
duyệt đi
\(M+N=2x^2+4xyz-10xy+2-y\)
\(M-N=-8x^2+2xyz-4+y\)
\(N-M=8x^2-2xyz+4-y\)
M+N=2x2+4xyz−10xy+2−y
M−N=−8x2+2xyz−4+y
N−M=8x2−2xyz+4−y
Mình làm tách riêng nha:
a) \(M+N\)
\(M+N=\left(3xyz-3x^2+5xy-1\right)+\left(5x^2+xyz-5xy+3-y\right)\)
\(M+N=\left(3xyz+xyz\right)+\left(-3x^2+5x^2\right)+\left(5xy-5xy\right)+\left(-1+3\right)-y\)
\(M+N=4xyz+2x^2+2-y\)
b) \(M-N\)
\(M-N=3xyz-3x^2+5xy-1-5x^2-xyz+5xy-3+y\)
\(=\left(3xyz-xyz\right)+\left(-3x^2-5x^2\right)+\left(5xy+5xy\right)+\left(-1-3\right)+y\)
\(=2xyz-8x^2+10xy-4+y\)
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