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Ta có : z = \(\frac{m}{n}\)= \(\frac{\frac{a+c}{2}}{\frac{b+d}{2}}=\frac{a+c}{b+d}=\frac{2m}{2n}\)
Nếu x < y thì \(\frac{a}{b}< \frac{a+c}{b+d}< \frac{c}{d}\)\(\Rightarrow\frac{a}{b}< \frac{2m}{2n}< \frac{c}{d}\)
\(\Rightarrow\frac{a}{b}< \frac{m}{n}< \frac{c}{d}\)\(\Rightarrow x< z< y\)
Nếu x > y thì : \(\frac{a}{b}>\frac{a+c}{b+d}>\frac{c}{d}\)\(\Rightarrow\frac{a}{b}>\frac{2m}{2n}>\frac{c}{d}\)
\(\Rightarrow\frac{a}{b}>\frac{m}{n}>\frac{c}{d}\)\(\Rightarrow x>z>y\)
Vậy ...
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Nếu x < y thì \(\frac{a}{b}\) < \(\frac{a+c}{b+d}\) < \(\frac{c}{d}\) hay \(\frac{a}{b}\) < \(\frac{2m}{2n}\) < \(\frac{c}{d}\) suy ra \(\frac{a}{b}\) < \(\frac{m}{n}\) < \(\frac{c}{d}\) , do đó x < z < y
tương tự nếu x > y thì x > z > y
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Lời giải:
\(\frac{y+z-x}{x}=\frac{z+x-y}{y}=\frac{x+y-z}{z}\)
\(\Leftrightarrow \frac{y+z}{x}-1=\frac{z+x}{y}-1=\frac{x+y}{z}-1\)
\(\Leftrightarrow \frac{y+z}{x}=\frac{z+x}{y}=\frac{x+y}{z}\)
\(\Leftrightarrow \frac{y+z}{x}+1=\frac{z+x}{y}+1=\frac{x+y}{z}+1\)
\(\Leftrightarrow \frac{y+z+x}{x}=\frac{z+x+y}{y}=\frac{x+y+z}{z}(*)\)
Nếu \(x+y+z=0\)
\(\Rightarrow x+y=-z; y+z=-x; z+x=-y\)
\(\Rightarrow B=(1+\frac{x}{y})(1+\frac{y}{z})(1+\frac{z}{x})=\frac{(x+y)(y+z)(z+x)}{yzx}=\frac{(-z)(-x)(-y)}{yzx}=-1\)
Nếu $x+y+z\neq 0$. Khi đó từ $(*)$ suy ra $x=y=z$
\(\Rightarrow B=(1+\frac{x}{y})(1+\frac{y}{z})(1+\frac{z}{x})=(1+\frac{x}{x})(1+\frac{x}{x})(1+\frac{x}{x})=(1+1)(1+1)(1+1)=8\)
Vậy................
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Z = a+c/2 :b+d/2 =a+c/2 ·2/b+d =a+c/b+d
X =a/b = a(b+d)/b(b+d) =ab+ad/b2+bd
Z= a+c/b+d =(a+c).b/(b+d).b =ab+ac/b2+bd
(+) Nếu a dương ; d< c => ad < ac => ab +ad < ab +ac => X < Z
(+) Nếu a âm ; d< c => ad > ac => ab + ad > ab + ac => X>Z
(+) nếu a dương ; d > c => ad > ac => ab + ad > ab + ac => X > Z
(+) ..................................... ........................................... Z >X
Z = a+c/2 :b+d/2 =a+c/2 ·2/b+d =a+c/b+d
X =a/b = a(b+d)/b(b+d) =ab+ad/b2+bd
Z= a+c/b+d =(a+c).b/(b+d).b =ab+ac/b2+bd
(+) Nếu a dương ; d< c => ad < ac => ab +ad < ab +ac => X < Z
(+) Nếu a âm ; d< c => ad > ac => ab + ad > ab + ac => X>Z
(+) nếu a dương ; d > c => ad > ac => ab + ad > ab + ac => X > Z
(+) ..................................... ........................................... Z >X
ta có x+m/x-n=y+m/x-n suy ra x+m/y+m=x-n/x-n=1
vậy x+m/y+m=1
suy ra x+m=y+m
suy ra x+m-m=y
suy ra x=y
suy ra x/y=1
=> x / x-n + m / x-n = y / x-n + m / x-n
=> x / x-n = y / x-n
=> x = y
=> \(\frac{x}{y}=1\)