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a: B nằm giữa A và N nên NB<NA
A nằm giữa M và N nên NA<NM
=>NB<NM
=>B nằm giữa M và N
=>BM và BN đối nhau
c: Tia đối nhau: BM và BN, AM và AB, MK và MA
Tia phân biệt: KN,MA,AB,BN
câu trl là b nhé bn :D
cách làm : ta có MA+AN=AM
mà M;A;N Cùng nằm trên đoạn thẳng MN
=>A nằm giữa M và N
=>đpcm
a) Các cặp tia đối nhau là:
+ Ax và Ay
+ Ox và Oy
+ Bx và By
+ Ex và Ey
b) Các tia trùng nhau gốc A là: AO, AB, AE, Ay.
Các tia trùng nhau gốc O là: OB, OE, Oy.
c) Theo câu a ta có 4 cặp góc đối nhau
\(\Rightarrow\) Có tất cả 8 tia phân biệt.
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