Question

[Phan Quynh anh]

cho A=\(\frac{196}{197}\)+\(\frac{197}{198}\)

      B=\(\frac{196+197}{197+198}\)

so sánh nha' giúp tui vs

Answer 1

[minh nguyen]

\(B=\frac{196+197}{197+198}=\frac{196}{197+198}+\frac{197}{197+198}\)

\(Vì\frac{196}{197}>\frac{196}{197+198}Và\frac{197}{198}>\frac{197}{197+198}\)

Suy ra \(\frac{196}{197}+\frac{197}{198}>\frac{196}{197+198}+\frac{197}{197+198}\)

Suy ra A>B