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a, -326-(115-326)=-326-(-326)-115=(-326+326)-115=-115
b,-13-18-(-42)-15=-13-18+42-15=-4
c,(-558+558)+(-50+50)=0+0=0
d,35-12+16=39
e,18.17-3.6.7=18.17-18.7=18.(17-7)=18.10=180
f,21.72-11.72+90.72+49.125.10
=21.72-11.72+90.72+72.1250
=72.(21-11+90+1250)
=72.1350=49.1350
=66150
\(27.332+93.43+57.61+69.57\\ =27.332+93.43+57.\left(61+69\right)\\ =27.332+93.43+57.130\\ =8964+3999+7410=20373\\ 34.75+75.66-65.100\\ =\left(34+66\right).75-65.100\\ =100.75-65.100\\ =100.\left(75-65\right)\\ =100.10=1000\\ \left(456.11+912\right).37:13:74\\ =5928:13:\left(74:37\right)\\ =456:2=228\\ 6^2:4.3+2.5^2\\ =36:4.3+2.25\\ =9.3+50=27+50=77\\ 5.4^2-18:3^2\\ =5.16-18:9\\ =80-2=78\\\left[\left(315+372\right).3+\left(372+315\right).7\right]:\left(26.13+74.14\right)\\ =687.\left(3+7\right):\left(338+1036\right)\\ 687.10:1374\\ =6870:1374=5\\ 12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\\ =12:\left[390:\left(500-370\right)\right]\\ =12:\left(390:130\right)=12:3=4\\ 192000-\left(1500.2+1800.3+1800.2:3\right)\\ =192000-\left(3000+5400+1200\right)\\ =192000-9600=182400\)
a)\(12-\left[25+\left(6+3\right)^2\right]\)
\(=12-\left[25+9^2\right]\)
\(=12-\left[25+81\right]\)
\(=12-106\)
\(=\left(-94\right)\)
b) \(315-\left(8^6\div8^4-12.3+7+7^3\right)\)
\(=316-\left(8^2-36+7+343\right)\)
\(=316-\left(64-43+343\right)\)
\(=316-\left(21+343\right)\)
\(=316-364\)
\(=\left(-48\right)\)
a) -132 + (176+132)
= -132+176+132
= -132+132+176
=0+176
= 176
b) 25. (-5).4.(-8)
= (25.4).[-5.(-8)]
= 100 . 40
= 4000
c) -37.52+37. (-48)
= -37.52+(-37).48
= -37.(52+48)
= -37.100
= -3700
d) 54 - 8.(6-23)
= 54 - 8. (-17)
= 54 - (-136)
= 54 + 136
= 190
e) -85 . 13 + 85 . 113
= 85 . (-13) + 85 . 113
= 85. (-13 + 113)
= 85.100
= 8500
f)2008-(107+2008)-75
= 2008 - 107 - 2008 - 75
= 2008 - 2008 - 107 - 75
= -107 - 75
= -182
a, \(\dfrac{7}{15}\)+\(\dfrac{18}{54}\)
= \(\dfrac{7}{15}\)+ \(\dfrac{1}{3}\)
= \(\dfrac{7}{15}\)+\(\dfrac{5}{15}\)
= \(\dfrac{12}{15}\) = \(\dfrac{4}{5}\) =0,8
b, \(\dfrac{12}{25}\)+\(\dfrac{23}{75}\)-\(\dfrac{1}{4}\)
= \(\dfrac{59}{75}\) -\(\dfrac{1}{4}\)
= \(\dfrac{161}{300}\)
c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)
\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)
\(=1-2=-1\)
Giải:
a)-1/12+4/3=-1/12+16/12=15/12=5/4
b)(-4/14-3/15)-(1/5-20/35-(-1)).7
=-17/35-22/35.7
=-17/35-22/5
=-171/35
c)3/5+-5/20+30/75+-7/4
=3/5+-1/4+2/5+-7/4
=(3/5+2/5)+(-1/4+-7/4)
=1+-2
=-1
d)5/6.-12/14+7/13
=-5/7+7/13
=-16/91
e)2/-9-5/-36-1/4
=-1/12-1/4
=-1/3
f)2/23+-5/12+7/18+21/23+-7/12
=(2/23+21/23)+(-5/12+-7/12)+7/18
=1+-1+7/18
=7/18