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K nha !
Mg + H2SO4 -------> MgSO4 + H2
MgSO4 + BaCl2 --------> MgCl2 + BaSO4
MgCl2 + 2KNO3 -------> 2KCl + Mg(NO3)2
Mg(NO3)2 + 2NaOH ------> Mg(OH)2 + 2NaNO3
Mg(OH)2 --------> MgO + H2O
MgO + H2SO4 -------> MgSO4 + H2O
\(MgCl_2\rightarrow Mg+Cl_2\uparrow\)
\(2Mg+O_2\rightarrow2MgO\)
\(MgO+H_2SO_4\rightarrow MgSO_4\downarrow+H_2O\)
\(MgSO_4+Ba\left(NO_3\right)2\rightarrow Mg\left(NO_3\right)_2+BaSO_4\downarrow\)
\(Mg\left(NO_3\right)_2+2NaOH\rightarrow Mg\left(OH\right)_2\downarrow+2NaNO_3\)
\(Mg\left(OH\right)_2\rightarrow MgO+H_2O\)
a) Fe+Cl3\(\rightarrow\)FeCl3
FeCl3+3NaOH\(\rightarrow\) Fe(OH)3\(\downarrow\)+3NaCl
2Fe(OH)3\(\underrightarrow{t^o}\) Fe2O3+3H2O
Fe2O3+3H2\(\underrightarrow{t^o}\) 3Fe+3H2O
Fe+2HCl\(\rightarrow\) FeCl2+H2
b)2Mg+O2\(\underrightarrow{t^0}\) 2MgO
MgO+H2SO4\(\rightarrow\) MgSO4+H2O
MgSO4+Ba(NO3)2\(\rightarrow\) BaSO4\(\downarrow\) Mg(NO3)2
Mg(NO3)2+2NaOH\(\rightarrow\) Mg(OH)2\(\downarrow\) 2NaNO3
Mg(OH)2+2HCl\(\rightarrow\) MgCl2+2H2O
c) ý này giống ý b thôi bạn.
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a.
2Al2O3 \(\underrightarrow{t^o}\)4Al + 3O2\(\uparrow\)
Al + 6HNO3 \(\rightarrow\) Al(NO3)3\(\downarrow\) + 3NO2 + 3H2O
Al(NO3)3 + NaOH \(\rightarrow\) Al(OH)3\(\downarrow\) + NaNO3
2Al(OH)3 \(\xrightarrow[criolit]{đpnc}\) Al2O3 + 3H2O
Al2O3 + 3H2SO4 \(\rightarrow\) Al2(SO4)3 + 3H2O
Al2(SO4)3 + 3BaCl2 \(\rightarrow\) 3BaSO4\(\downarrow\) + 2AlCl3
2AlCl3 \(\xrightarrow[criolit]{đpnc}\) 2Al + 3Cl2\(\uparrow\)
2Al + 3CuSO4 \(\rightarrow\) 3Cu + Al2(SO4)3
Đánh số theo thứ tự từ trái qua phải:
\(\left(1\right)Mg+\dfrac{1}{2}O_2\underrightarrow{t^o}MgO\\ \left(2\right)MgO+2HCl\rightarrow MgCl_2+H_2O\\ \left(3\right)MgCl_2+2AgNO_3\rightarrow Mg\left(NO_3\right)_2+2AgCl\\ \left(4\right)Mg\left(NO_3\right)_2+2NaOH\rightarrow Mg\left(OH\right)_2+2NaNO_3\\ \left(5\right)Mg\left(OH\right)_2\underrightarrow{t^o}MgO+H_2O\\ \left(6\right)MgO+H_2SO_4\rightarrow MgSO_4+H_2O\\ \left(7\right)MgSO_4+Na_2CO_3\rightarrow MgCO_3+Na_2SO_4\\ \left(8\right)MgCO_3+CO_2+H_2O\rightarrow Mg\left(HCO_3\right)_2\)
\(2Mg+O_2\xrightarrow[]{t^0}2MgO\\ MgO+2HCl\rightarrow MgCl_2+H_2O\\ MgCl_2+2AgNO_3\rightarrow Mg\left(NO_3\right)_2+2AgCl\downarrow\\ Mg\left(NO_3\right)_2+2NaOH\rightarrow Mg\left(OH\right)_2\downarrow+2NaNO_3\\ Mg\left(OH\right)_2\xrightarrow[]{t^0}MgO+H_2O\\ Mg+H_2SO_4\rightarrow MgSO_4+H_2\uparrow\\ MgSO_4+K_2CO_3\rightarrow MgCO_3\downarrow+K_2SO_4\\ MgCO_3+H_2O+CO_2\rightarrow Mg\left(HCO_3\right)_2\)
a)
4Al + 3O2\(\rightarrow\) 2Al2O3
Al2O3 +6HNO3\(\rightarrow\) 2Al(NO3)3 + 3H2O
Al(NO3)3 + 3NaOH \(\rightarrow\)Al(OH)3 + 3NaNO3
2Al(OH)3 \(\underrightarrow{^{to}}\) Al2O3 + 3H2O
Al2O3 +6HCl \(\rightarrow\) 2AlCl3 + 3H2O
AlCl3 không điện phân nóng chảy được \(\rightarrow\) Al2O3 \(\underrightarrow{^{\text{đpnc}}}\)2Al + \(\frac{3}{2}\)O2
b) 2Fe + 3Cl2 \(\rightarrow\) 2FeCl3
FeCl3 + 3NaOH \(\rightarrow\)Fe(OH)3 + 3NaCl
2Fe(OH)3\(\rightarrow\)Fe2O3 + 3H2O
Fe2O3 + 3CO \(\rightarrow\)2Fe + 3CO2
Fe + 2HCl\(\rightarrow\) FeCl2 + 2
FeCl2 + 2AgNO3\(\rightarrow\)Fe(NO3)2 + 2AgCl (thường ra Fe+3 )
c) 2Mg + O2\(\rightarrow\)2MgO
MgO + 2HCl \(\rightarrow\) MgCl2 + H2O
MgCl2 + 2NaOH \(\rightarrow\) Mg(OH)2 + 2NaCl
Mg(OH)2 + H2SO4 \(\rightarrow\)MgSO4 + 2H2O
MgSO4 + BaCl2 \(\rightarrow\) MgCl2 + BaSO4
d) Cu(OH)2\(\underrightarrow{^{to}}\) CuO + H2O
CuO + H2SO4\(\rightarrow\)CuSo4 + H2O
CuSO4 + BaCl2 \(\rightarrow\) BaSO4 + CuCl2
CuCl2 + 2AgNO3 \(\rightarrow\) Cu(NO3)2 + 2AgCl
Fe + Cu(NO3)2\(\rightarrow\) Fe(NO3)2 + Cu
Cu + \(\frac{1}{2}\)O2 \(\rightarrow\) CuO
e) 4Na + O2\(\rightarrow\) 2Na2O
Na2O + H2O \(\rightarrow\) 2NaOH
2NaOH + CO2 \(\rightarrow\)Na2CO3 + H2O
Na2CO3 + H2SO4\(\rightarrow\) Na2SO4 + CO2 + H2O
Na2SO4 + BaCl2 \(\rightarrow\)BaSO4 + 2NaCl
NaCl + AgNO3\(\rightarrow\) AgCl + NaNO3
f) Fe3O4 + 4CO\(\rightarrow\) 3Fe + 4CO2
2Fe + 3Cl2 \(\rightarrow\)2FeCl3
FeCl3 + 3AgNO3 \(\rightarrow\) Fe(NO3)3 +3AgCl
Fe(NO3)3 + 3NaOH \(\rightarrow\) Fe(OH)3 + 3NaNO3
Lần sau đăng tách riêng ra nhé
Nhìn rối mắt lắm
a) Al -> Al2O3-> Al(NO3)3-> Al(OH)3 -> Al2O3 -> AlCl3 -> Al
(1) 2A1 + O2 t0→ Al2O3
(2) Al2O3 + 6HCl → 2AlCl3 + 3H2O
(3) Al(NO3)3 + 3NaOH (vừa đủ) → 3NaNO3 + Al (OH)3
(4) 2Al(OH)3 →t0 Al2O3+ ЗН2О
(5) 2Al2O3 đpnc−−→đpnc 4Al + 3O2
(6) 2Al + 3Cl2 t→t0 2AlCl3
b) Fe -> FeCl3 -> Fe(OH)3 -> Fe2O3-> Fe -> FeCl2 -> Fe(NO3)3
(1) 2Fe + 3Cl2 → 2FeCl3
(2) FeCl3 + 3NaOH → 3NaCl + Fe(OH)3
(3) 2Fe(OH)3 → Fe2O3 + 3H2O
(4) Fe2O3 + H2→ Fe + H2O
(5) 3Fe + 2HCl → 2FeCl2 +H2↑
(6) Fe(NO3)3+3NaOH ➞Fe(OH)3 +3Na(NO3)
dài wá mình trả lời những câu còn lại sau : thông cảm cho mk nha❗❕
A:
\(Cu\left(OH\right)_2--to->CuO+H_2O\)
\(CuO+2HCl-->CuCl_2+H_2O\)
\(CuCl_2+2NaOH-->Cu\left(OH\right)_2+2NaCl\)
\(Cu\left(OH\right)_2+H_2SO_4-->CuSO_4+2H_2O\)
B:
\(Mg\left(OH\right)_2--to->MgO+H_2O\)
\(MgO+2HCl-->MgCl_2+H_2O\)
\(MgCl_2+2NaOH-->Mg\left(OH\right)_2+2NaCl\)
\(Mg\left(OH\right)_2+H_2SO_4-->MgSO_4+2H_2O\)
A: Cu(OH)2 \(\underrightarrow{t^o}\) CuO + H2O
CuO + 2HCl \(\rightarrow\) CuCl2 + H2O
CuCl2 +2 NaOH \(\rightarrow\) Cu(OH)2 + NaCl
Cu(OH)2 + H2SO4 \(\rightarrow\) CuSO4 + 2H2O
B: Mg(OH)2 \(\underrightarrow{t^o}\) 2MgO + H2O
MgO + 2HCl \(\rightarrow\) MgCl2 + H2O
MgCl2 + 2NaOH \(\rightarrow\) Mg(OH)2 + NaCl
Mg(OH)2 + H2SO4 \(\rightarrow\) MgSO4 + 2H2O
Giải được câu A rồi thì câu B làm tương tự thôi
a)
$CaCO_3 \xrightarrow{t^o} CaO + CO_2$
$CaO + H_2O \to Ca(OH)_2$
$Ca(OH)_2 + 2HCl \to CaCl_2 + 2H_2O$
$CaCl_2 + 2AgNO_3 \to Ca(NO_3)_2 + 2AgCl$
b)
$2Mg + O_2 \xrightarrow{t^o} 2MgO$
$MgO + 2HCl \to MgCl_2 + H_2O$
$MgCl_2 + 2KOH \to Mg(OH)_2 + 2KCl$
$Mg(OH)_2 + H_2SO_4 \to MgSO_4 + 2H_2O$
\(2Mg+O_2\rightarrow2MgO\)
\(MgO+H_2SO_4\rightarrow MgSO_4+H_2O\)
Câu 2 :
\(Mg\underrightarrow{1}MgO\underrightarrow{2}MgSO_4\underrightarrow{3}Mg\left(OH\right)_2\underrightarrow{4}MgCl_2\underrightarrow{5}Mg\left(NO_3\right)_2\underrightarrow{6}MgCO_3\)
(1) \(2Mg+O_2\underrightarrow{t^o}2MgO\)
(2) \(MgO+H_2SO_4\rightarrow MgSO_4+H_2O\)
(3) \(MgSO_4+2NaOH\rightarrow Mg\left(OH\right)_2+Na_2SO_4\)
(4) \(Mg\left(OH\right)_2+2HCl\rightarrow MgCl_2+2H_2O\)
(5) \(MgCl_2+2AgNO_3\rightarrow Mg\left(NO_3\right)_2+2AgCl\)
(6) \(Mg\left(NO_3\right)_2+Na_2CO_3\rightarrow MgCO_3+2NaNO_3\)
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