Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1) x-2x-3x-4x-5x=-13x thay x=-8 => -13x=(-8).(-13)=104
2)(x+1)-2(x+1)-3(x+1)-4(x+1)-5(x+1)=-13(x+1) thay x=-8 => -13(x+1)=(-13).(-7)-91
<=> ( x + x + x + .... + x + x ) + ( 1 + 2 + 3 + .... + 49 + 50 ) = 1425
<=> 50x + { [ 50.( 50 + 1 ) ] : 2 } = 1425
=> 50x + 1275 = 1425
=> 50x = 1425 - 1275
=> 50x = 150
=> x = 150 : 50 = 3
=> (x+ x+ x +...+ x) + (1+2+..+ 50) = 1425
=> 50x + 1275=1425
=> 50x = 150
=> x=3
**** mk nha!
ban viet sai de bai roi khong phai1/27 ma la1/21
ta co: 1/21+1/28+1/36+...+2/x(x+1)=2/9
1/21.2+1/28.2+1/36.2+...+2/x(x+1).2=2/9.1/2
1/42+1/56+1/72+...+1/x(x+1)=1/9
1/6.7+1/7.8+1/8.9+...+1/x(x+1)=1/9
1/6-1/7+1/7-1/8+1/8-1/9+...+1/x-1/x+1=1/9
1/6-1/x+1=1/9(khu lien tiep)
1/x+1=1/6-1/9
1/x+1=1/18
=>x+1=18
=>x=17
khu lien tiep là khu liên tiếp đúng ko bạn, tại bạn đánh ko dấu nên mình ko hiểu
có [x-y]2=1
suy ra [x-y]mũ 2= 1 mũ 2
suy ra x-1=1
x=1+1
x=2
\(\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+....+\frac{1}{8.9.10}\right).x=\frac{23}{45}\)
\(\Leftrightarrow\left[\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+....+\frac{1}{8.9}-\frac{1}{9.10}\right)\right]x=\frac{23}{45}\)
\(\Leftrightarrow\left[\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{9.10}\right)\right].x=\frac{23}{45}\)
\(\Leftrightarrow\left(\frac{1}{2}.\frac{44}{90}\right).x=\frac{23}{45}\)
\(\Leftrightarrow\frac{11}{45}.x=\frac{23}{45}\Rightarrow x=\frac{23}{45}:\frac{11}{45}=\frac{23}{11}\)
nhung sao banj khong phan h ra ro rang,chang nhe den do khong phan h duoc sao
1.2(x-1)+(x-2)=x-4
2x-2+x-2=x-4
2x+ x-x=2+2-4
2x=0
=> x=0
Vậy x=0
\(\frac{1}{5}+\frac{1}{3}\left(x+1\right)=\frac{1}{4}\)
\(\frac{1}{3}\left(x+1\right)=\frac{1}{4}-\frac{1}{5}\)
\(\frac{1}{3}\left(x+1\right)=\frac{1}{20}\)
\(x+1=\frac{1}{20}:\frac{1}{3}\)
\(x+1=\frac{3}{20}\)
\(x=\frac{3}{20}-1\)
\(x=-\frac{17}{20}\)
\(\frac{1}{5}+\frac{1}{3}\left(x+1\right)=\frac{1}{4}\)
\(\frac{1}{3}\left(x+1\right)=\frac{1}{4}-\frac{1}{5}\)
\(\frac{1}{3}\left(x+1\right)=\frac{1}{20}\)
\(x+1=\frac{1}{20}:\frac{1}{3}\)
\(x-1=\frac{3}{20}\)
\(x=\frac{3}{20}-1\)
\(x=-\frac{17}{20}\)