Question

[Khánh Linh]

BT1: Tìm x, biết:

1) \(x+\text{|}\dfrac{1}{2}-\dfrac{1}{3}\text{|}=\text{|}\dfrac{-2}{3}-\dfrac{1}{4}\text{|}\)

Answer 1

[Đỗ Thanh Hải]

\(x+\left|\dfrac{1}{2}-\dfrac{1}{3}\right|=\left|\dfrac{-2}{3}-\dfrac{1}{4}\right|\)

\(x+\left|\dfrac{1}{6}\right|=\left|\dfrac{-11}{12}\right|\)

\(x+\dfrac{1}{6}=\dfrac{11}{12}\)

\(x=\dfrac{11}{12}-\dfrac{1}{6}\)

\(x=\dfrac{3}{4}\)

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