Question

[Ngô Hiếu]

B=m(m-n+1)-n(n+1-m) với m=\(\dfrac{-2}{3}\),n=\(\dfrac{-1}{3}\)

Answer 1

[Nguyễn Hoàng Minh]

\(B=m^2-mn+m-n^2-n+mn\\ B=m^2+m-n^2-n\\ B=\left(\dfrac{-2}{3}\right)^2-\dfrac{2}{3}-\left(\dfrac{-1}{3}\right)^2+\dfrac{1}{3}\\ B=\dfrac{4}{9}-\dfrac{2}{3}-\dfrac{1}{9}+\dfrac{1}{3}=0\)

Answer 2

[Lấp La Lấp Lánh]

\(B=m\left(m-n+1\right)-n\left(n+1-m\right)=m\left(m+n+1-2n\right)-n\left(m+n+1-2m\right)=\left(m+n\right)\left(m+n+1\right)-2mn+2mn=\left(m+n\right)\left(\dfrac{-2}{3}-\dfrac{1}{3}+1\right)-4mn=0-0=0\)