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\(1,-\dfrac{1}{2}.\dfrac{4}{7}+\dfrac{5}{14}=-\dfrac{2}{7}+\dfrac{5}{14}\)
\(=\dfrac{1}{14}\)
\(2,\dfrac{1}{2}-\dfrac{3}{4}+2021^0=-\dfrac{1}{4}+1\)
\(=\dfrac{3}{4}\)
\(3,\left(-\dfrac{1}{5}\right)^2+\dfrac{1}{5}-2.\left(\dfrac{-1}{2}\right)^3-\dfrac{1}{2}\)
\(=\dfrac{1}{25}+\dfrac{1}{5}-2.\left(-\dfrac{1}{8}\right)-\dfrac{1}{2}\)
\(=\dfrac{6}{25}-\left(-\dfrac{1}{4}\right)-\dfrac{1}{2}=\dfrac{6}{25}+\dfrac{1}{4}-\dfrac{1}{2}\)
\(=\dfrac{49}{100}-\dfrac{1}{2}=-\dfrac{1}{100}\)
\(4,\left(3-\dfrac{1}{4}+\dfrac{2}{3}\right)^2:2022^0=\left(\dfrac{11}{4}+\dfrac{2}{3}\right)^2:1\)
\(=\dfrac{1681}{144}:1=\dfrac{1681}{144}\)
\(5,\left(\dfrac{3}{7}\right)^0.1^{15}+\dfrac{7}{9}:\left(\dfrac{2}{3}\right)^2-\dfrac{4}{5}\)
\(=1.1+\dfrac{7}{9}:\dfrac{4}{9}-\dfrac{4}{5}\)
\(=1+\dfrac{7}{9}.\dfrac{9}{4}-\dfrac{4}{5}=1+\dfrac{7}{4}-\dfrac{4}{5}\)
\(=\dfrac{11}{4}-\dfrac{4}{5}=\dfrac{39}{20}\)
\(6,\left\{\left[\left(\dfrac{1}{25}-0,6\right)^2:\dfrac{49}{125}\right].\dfrac{5}{6}\right\}-\left[\left(-\dfrac{1}{3}\right)+\dfrac{1}{2}\right]\)
\(=\left\{\left[\left(-\dfrac{14}{25}\right)^2.\dfrac{125}{49}\right].\dfrac{5}{6}\right\}-\dfrac{1}{6}\)
\(=\left[\left(\dfrac{196}{625}.\dfrac{125}{49}\right).\dfrac{5}{6}\right]-\dfrac{1}{6}\)
\(=\left(\dfrac{196.125}{625.49}.\dfrac{5}{6}\right)-\dfrac{1}{6}=\left(\dfrac{49.4.125}{5.125.49}.\dfrac{5}{6}\right)-\dfrac{1}{6}\)
\(=\left(\dfrac{4}{5}.\dfrac{5}{6}\right)-\dfrac{1}{6}=\dfrac{4}{6}-\dfrac{1}{6}=\dfrac{3}{6}=\dfrac{1}{2}\)
\(7,-\dfrac{5}{14}+\dfrac{3}{8}-\dfrac{2}{14}-\dfrac{3}{8}+\dfrac{1}{2}=\left(-\dfrac{5}{14}-\dfrac{2}{14}\right)+\left(\dfrac{3}{8}-\dfrac{3}{8}\right)+\dfrac{1}{2}\)
\(=-\dfrac{1}{2}+\dfrac{1}{2}=0\)
\(8,-\dfrac{3}{17}.\dfrac{2}{3}+\dfrac{2}{3}.\left(\dfrac{-14}{17}\right)=\dfrac{2}{3}.\left[-\dfrac{3}{17}+\left(-\dfrac{14}{17}\right)\right]\)
\(=\dfrac{2}{3}.\left(-1\right)=-\dfrac{2}{3}\)
#\(Cụt\)
#\(yGLinh\)
Bài 2:
Chu vi hình chữ nhật:
\(\left(4\dfrac{3}{7}+2\dfrac{1}{5}\right).2=\left(\dfrac{31}{7}+\dfrac{11}{5}\right).2=\dfrac{232}{35}.2=\dfrac{464}{35}\left(m\right)\)
Diện tích hình chữ nhật:
\(4\dfrac{3}{7}.2\dfrac{1}{5}=\dfrac{31}{7}.\dfrac{11}{5}=\dfrac{341}{35}\left(m^2\right)\)
So sánh \(\frac{-19}{49}\)và\(\frac{-23}{27}\)
Quy đồng lên ta được: \(\frac{-19}{49}=\frac{\left(-19\right).47}{49}=\frac{-893}{2303}\)và\(\frac{-23}{47}=\frac{\left(-23\right).49}{47.49}=\frac{-1127}{2303}\)
Mà: \(\frac{-893}{2303}>\frac{-1127}{2303}\)\(\Rightarrow\frac{-19}{49}>\frac{-23}{47}\)
dạ em lớp 5 ko bít làm bài lớp 7 ạ còn anh em đang ngủ thật sự xin lỗi anh
Em cần hỗ trợ tất cả sao?
dạ ko ạ
chỉ câu 8 thui ạ