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a) \(\frac{27}{36}=\frac{3}{4}\)
b) \(\frac{45}{60}=\frac{3}{4}\)
c) \(\frac{2}{4}=\frac{1}{2}\)
d) \(\frac{10}{12}=\frac{5}{6}\)
e) \(\frac{112}{252}=\frac{4}{9}\)
Đúng nha bạn !!@@
\(\frac{1}{3}+\frac{3}{4}x\frac{5}{9}=\frac{1}{3}+\frac{5}{12}=\frac{3}{4}\)
\(\frac{7}{12}-\frac{5}{4}x\frac{2}{15}=\frac{7}{12}-\frac{1}{6}=\frac{5}{12}\)
\(y+\frac{1}{4}=\frac{7}{8}-\frac{3}{8}=y+\frac{1}{4}=\frac{1}{2}=\frac{1}{2}-\frac{1}{4}=\frac{1}{4}\)
\(y-\frac{5}{12}=\frac{2}{3}-\frac{1}{4}=y-\frac{5}{12}=\frac{5}{12}=\frac{5}{12}+\frac{5}{12}=\frac{5}{6}\)
\(\frac{12}{7}xy=\frac{16}{21}=\frac{16}{21}:\frac{12}{7}=\frac{4}{9}\)
\(\frac{5}{4}:y=\frac{7}{12}=\frac{5}{4}:\frac{7}{12}=\frac{15}{7}\)
(12/7x4/13)+(12/14x14/26)+(6/7x2/13)
= 48/91 + 6/13 + 12/91
= 90/91 + 12/91
= 102/91
a/ \(\left[\frac{4}{6}+\frac{14}{6}\right]+\left[\frac{7}{13}+\frac{19}{13}\right]+\left[\frac{17}{9}+\frac{1}{9}\right]=\frac{18}{6}+\frac{26}{13}+\frac{18}{9}=3+2+2=7\)
Bài 1: a) Cách 1
Ta có: 7/5=49/35 ; 5/7=25/35
Do 49/35 > 25/35 nên 7/5 > 5/7
Cách 2
Ta thấy 7/5 >1 mà 5/7 < 1 nên 7/5 > 5/7
Bài 2: 7/3; 7/5; 7/6
Bài 3: a)5/9
b)1/2
bài 1:a)
:Ta có:7/5=49/35
5/7=25/35 vì 49/35>25/35suy ra 7/5>5/7
b) Ta có:14/16<1<24/21 nên 14/16<24/21
Bài 2: 7/3>7/5>7/6
Bài 3:a) Vì phần TS và phần MS đều có 6,7,8 Nên ta khử 678 thì còn 5/9 vậy bằng 5/9
b) tách 42 thành 6*7 và 32=16*2 Ta có:6*7*16*2/12*14*16 Sau đó ta khử 16,Tiếp tục ta lấy 12/6,14/7 rồi sau đó tính lại thì =1/2
\(\frac{1}{2}:\frac{3}{2}:\frac{5}{4}:\frac{6}{5}:\frac{7}{6}:\frac{8}{7}\)
\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{4}{5}\cdot\frac{5}{6}\cdot\frac{6}{7}\cdot\frac{7}{8}\)
\(=\frac{1\cdot\left(2\cdot5\cdot6\cdot7\right)}{8\cdot3\cdot\left(2\cdot5\cdot6\cdot7\right)}\)
\(=\frac{1}{24}\)
\(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot\frac{5}{6}\cdot\frac{6}{7}\cdot\frac{7}{8}\cdot\frac{8}{9}\cdot\frac{9}{10}\)
\(=\frac{1\cdot\left(2\cdot3\cdot4\cdot5\cdot6\cdot7\cdot8\cdot9\right)}{\left(2\cdot3\cdot4\cdot5\cdot6\cdot7\cdot8\cdot9\right)\cdot10}\)
\(=\frac{1}{10}\)
\(\frac{2}{3}.\frac{4}{7}=\frac{8}{21}\)
\(\frac{3}{11}.2=\frac{6}{11}\)
\(4.\frac{2}{7}=\frac{8}{7}\)
\(\frac{8}{21}:\frac{2}{3}=\frac{8}{21}.\frac{3}{2}=\frac{21}{2.21}=\frac{1}{2}\)
\(\frac{3}{7}.\frac{7}{3}=\frac{21}{21}=1\)
\(\frac{3}{7}:\frac{3}{7}=\frac{3}{7}.\frac{7}{3}=\frac{21}{21}=1\)
lỡ tay bấm gửi trả lời luôn
\(\frac{2}{3}.\frac{1}{6}.\frac{9}{11}=\frac{2.9}{18.11}=\frac{2.9}{2.9.11}=\frac{1}{11}\)
\(\frac{2.3.4}{2.3.4.5}=\frac{6.4}{6.4.5}=\frac{24}{24.5}=\frac{1}{5}\)
\(\left(2.8x-32\right):\frac{2}{3}=90\)
\(2.8\cdot x-32=90\cdot\frac{2}{3}\)
\(\frac{14}{5}x-32=60\)
\(\frac{14}{5}x=60+32\)
\(\frac{14}{5}x=92\)
\(x=\frac{230}{7}\)
B , c , d tương tự
a) Tìm y:
\(\frac{1}{3}\times y=\frac{1}{6}\)
\(y=\frac{1}{6}\div\frac{1}{3}\)
\(\Leftrightarrow y=\frac{1}{6}\times\frac{3}{1}\)
\(y=\frac{3}{6}\Leftrightarrow y=\frac{1}{2}\)
b) Tính giá trị của biểu thức:
\(\frac{2}{7}\div\frac{2}{3}-\frac{1}{7}\)
\(=\frac{2}{7}\times\frac{3}{2}-\frac{1}{7}\)
\(=\frac{2\times3}{7\times2}-\frac{1}{7}\)
\(=\frac{3}{7}-\frac{1}{7}=\frac{2}{7}\)
a)\(\frac{1}{3}\times y=\frac{1}{6}\)
\(y=\frac{1}{6}:\frac{1}{3}\)
\(y=\frac{1}{6}\times3\)
\(y=\frac{3}{6}=\frac{1}{2}\)
b)\(\frac{2}{7}:\frac{2}{3}-\frac{1}{7}\)
\(=\frac{2}{7}\times\frac{3}{2}-\frac{1}{7}\)
\(=\frac{3}{7}-\frac{1}{7}=\frac{2}{7}\)