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Ta có
(2x-1)^10 = 49^5
=> (2x-1)^10 = (7^2)^5
=> (2x-1)^10 = 7^10
=> 2x-1 = 7
=> 2x= 8
=> x=4
a) Ta có: \(\dfrac{4}{5}-3\left|x\right|=\dfrac{1}{5}\)
\(\Leftrightarrow3\left|x\right|=\dfrac{4}{5}-\dfrac{1}{5}=\dfrac{3}{5}\)
\(\Leftrightarrow\left|x\right|=\dfrac{1}{5}\)
hay \(x\in\left\{\dfrac{1}{5};-\dfrac{1}{5}\right\}\)
b) Ta có: \(4x-\dfrac{1}{2}x+\dfrac{3}{5}x=\dfrac{4}{5}\)
nên \(\dfrac{41}{10}x=\dfrac{4}{5}\)
hay \(x=\dfrac{8}{41}\)
c) Ta có: \(\left(2x-8\right)\left(10-5x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-8=0\\10-5x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=8\\5x=10\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=2\end{matrix}\right.\)
d) Ta có: \(\dfrac{3}{4}+\dfrac{1}{4}\left|2x-1\right|=\dfrac{7}{2}\)
\(\Leftrightarrow\dfrac{1}{4}\left|2x-1\right|=\dfrac{7}{2}-\dfrac{3}{4}=\dfrac{14}{4}-\dfrac{3}{4}=\dfrac{11}{4}\)
\(\Leftrightarrow\left|2x-1\right|=11\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=11\\2x-1=-11\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=12\\2x=-10\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-5\end{matrix}\right.\)
a) Ta có: \(\left(2x-8\right)\left(2x+10\right)\ge0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-8\ge0\\2x+10\le0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x\ge4\\x\le-5\end{matrix}\right.\)
b) Ta có: \(\left(\left|x\right|+5\right)\left(x-3\right)< 0\)
nên x-3<0
hay x<3
a) Ta có: \(\dfrac{1}{4}-\left|x+\dfrac{1}{2}\right|=\dfrac{1}{8}\)
\(\Leftrightarrow\left|x+\dfrac{1}{2}\right|=\dfrac{1}{8}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{1}{8}\\x+\dfrac{1}{2}=-\dfrac{1}{8}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-3}{8}\\x=\dfrac{-5}{8}\end{matrix}\right.\)
(2x - 1)10 = 495
(2x-1)10=(72)5
(2x-1)10=710
=> 2x-1 = 7 hoặc 2x-1 = -7
nếu 2x-1 = 7 => x=4
nếu 2x-1=-7 => x=-3
(2x-1)10 = 495
(2x-1)10 = 710
hoặc (2x-1) = (-7)10
2x-1=7 hoặc 2x-1=-7
x=4 hoặc x=-3
\(\left(2x-1\right)^{10}=49^5\)
\(\left(2x-1\right)^{10}=7^{2.5}=7^{10}\)
=>\(2x-1=7\)
=>\(2x=7+1=8\)
=>x=\(8:2=4\)
=>(2x-1)10=(72)5
=>(2x-1)10=710
=> 2x-1=7
=>2x=8
=>x=4
tick nha
(2x-1)10=495
(2x-1)2.5=495
((2x-1)2)5=49
(2x-1)2=72
(2x-1)=7
2x=7+1
2x=8
x=8:2
x=4
(2x-1)10 = 495 = 710
2x-1 = 7
x=8/2 = 4
( 2x - 1) 10 = 495
=> (2x)10 - (110) = 282475249
2x10 - 1 = 282475249
2x10 = 282475250
=> x10 = 141237625
=> x = ........... tự làm nhé