Question

[Phạm Thu Phương]

Bài 1: Tìm số nguyên x:

{-3x+2.[45-x-3(3x+7)-2x]+4x}=55-103

-57:[-2.(2x+1)^2-(-9)^0=-106

Answer 1

[๖²⁴ʱんuﾘ ｲú❄✎﹏]

\(\left\{-3x+2\left[45-x-3\left(3x+7\right)-2x\right]+4x\right\}=55-103\)

\(\left\{-3x+2\left[45-x-9x-21-2x\right]+4x\right\}=-48\)

\(-3x+90-2x-18x-42-4x+4x=-48\)

\(-3x-2x-18x-4x+4x=-48-90+42\)

\(-23x=-96\Leftrightarrow x=\frac{96}{23}\)

Answer 2

[๖²⁴ʱんuﾘ ｲú❄✎﹏]

đag rảnh nên ... lm nốt 

\(-57:\left[-2\left(2x+1\right)^2-\left(-9\right)^0\right]=-106\)

\(-2\left(2x+1\right)^2+1=57\)

\(-2\left(2x+1\right)^2=56\)

\(\left(2x+1\right)^2=-28\)

\(\Rightarrow\orbr{\begin{cases}2x+1=-2\sqrt{7}\\2x+1=2\sqrt{7}\end{cases}\Rightarrow\orbr{\begin{cases}2x=-1-2\sqrt{7}\\2x=-1+2\sqrt{7}\end{cases}}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{-1-2\sqrt{7}}{2}\\x=\frac{-1+2\sqrt{7}}{2}\end{cases}}\)