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a, = 600
b, = 13
c, = 23900
d, = 11
Bài này dễ lắm. Chỉ cần một quyển nháp là bạn giải ngon ơ! Đâu cần hỏi trên olm đâu
a) \(9\cdot2^3-72:2^2\)
\(=72-18=54\)
b) \(125\cdot26+5^3\cdot32+25\cdot42\cdot5\)
\(=125\cdot26+125\cdot32+125\cdot42\)
\(=125\cdot\left(26+32+42\right)=125\cdot100=12500\)
c) \(5871:\left[928-\left(247-82\right)\cdot5\right]+2012^0\)
\(=5871:\left[928-\left(247-82\right)\cdot5\right]+1\)
\(=5871:\left(928-165\cdot5\right)+1\)
\(=5871:103+1\)
\(=58\)
d) \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=-100\)
a, \(9.2^3-\frac{72}{2^2}=9.8-\frac{72}{4}=72-18=54\)
b, \(125.26+5^3.32+25.42.5\)
\(=125.26+125.32+125.42\)
\(=125.\left(26+32+42\right)\)
\(=125.100\)
\(=12500\)
c, \(\frac{5871}{\left[928-\left(247-82\right).5\right]}+2012^0\)
\(=\frac{5871}{103}+1\)
\(=57+1\)
\(=58\)
d, \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=0+100\)
\(=100\)
\(a,27.75+27.25\)
\(=27.\left(75+25\right)\)
\(=27.100\)
\(=2700\)
\(b,\left(-6\right)+20+\left(-4\right)\)
\(=\left(-6-4\right)+20\)
\(=-10+20\)
\(=10\)
\(c,2^2.3^1-\left(1^{2012}+2012^0\right):2\)
\(=4.3-\left(1+1\right):2\)
\(=12-2:2\)
\(=12-1\)
\(=11\)
a)27.75+27.25
=27.(75+25)
=27.100
=2700
b)(-6)+20+(-4)
=[(-6)+(-4)]+20
=(-10)+20
=10
c)22.3-(12012+20120):2
=12-2:2
=12-1
=11
a,113-3+20
=1328+20
=1348
b,300+7781+1425
=9506
c,7+36-40
=43-40=3
a,
115 : 112 - 33 : ( 11 + 23 ) + 22 x 30 x 5
= 11( 5 - 2 ) - 27 : ( 1 + 8 ) + 4 x 1 x 5
= 113 - 27 : 9 + 4 x 5
= 1331 - 3 + 20
= 1328 + 20
= 1348
b,
12 x 25 + 31 x 251 + 57x 25
= 12 x 25 + 57 x 25 + 31 x 251
= ( 12 + 57 ) x 25 + 31 x 251
= 69 x 25 + 31 x 251
= 1725 + 7781
= 9506
c,
15 - 23 + 4 x 32 - 5 x 8
= 15 - 8 + 4 x 9 - 40
= 15 - 8 + 36 - 40
= 7 + 36 - 40
= 43 - 40
= 3
Câu 2:
a: \(=9\cdot8-72:4=72-18=54\)
b: \(=125\cdot26+125\cdot32+125\cdot42\)
\(=125\left(26+32+42\right)=125\cdot100=12500\)
c: \(=5871:\left(928-825\right)+1=5871:103+1=57+1=58\)
d: \(=2012+78-178-2012=-100\)
b/1.2.3.....2013 - 1.2.3....2012-1.2.3...20122
= (1.2.3...2012.2013-1.2.3...2012)-1.2.3...2012.2012
= 1.2.3...2012(2013-1-2012)
=1.2.3...2012.0=0
a) Ta có: 123+236+77+164
=(123+77)+(236+164)
=200+400=600
b) Ta có: \(2^5\cdot2^3-\frac{3^{13}}{3^8}\)
\(=2^8-3^5=256-243=13\)
c) Ta có \(239\cdot147-239\cdot47\)
\(=239\left(147-47\right)=239\cdot100=23900\)
d) Ta có: \(22\cdot31-\frac{\left(1^{2012}+2012^0\right)}{\left|-2\right|}\)
\(=22\cdot31-\frac{1+1}{2}=22\cdot31-1=682-1=681\)