Question

[Đức Đạt Đỗ (Đạt 301 Channel)]

Bài 1: Thu gọn đơn thức ( a là hằng só )

a) \(1\dfrac{1}{4}x^2y\left(\dfrac{-5}{6}xy\right)^0.\left(-2\dfrac{1}{3}xy\right)\)

b) \(\dfrac{1}{2}x.\dfrac{1}{4}x^2.\dfrac{x^3}{8}.2y.4y^2.x^3\)

c) \(\left(\dfrac{-9}{2}\right)^3.3xy\left(4a^2x^3\right)\left(4\dfrac{1}{3}ay^2\right)\)

d) \(\left(\dfrac{1}{3}xy^2\right)^3\left(\dfrac{-3}{7}x^4y\right)^2\)

Answer 1

[KAl(SO4)2·12H2O]

T giải thử thôi nhé :w

a) \(1\frac{1}{4}x^2y\left(\frac{-5}{6}xy\right)^0.\left(-2\frac{1}{3}xy\right)\)

\(=\frac{5}{4}x^2y\left(\frac{-5}{6}xy\right)^0.\left(-\frac{5}{2}xy\right)\)

\(=1.\frac{5}{4}x^2y\left(-\frac{5}{2}xy\right)\)

\(=-\frac{5}{4}x^2y.1.\frac{5}{2}xy\)

\(=-1.\frac{5}{4}.\frac{5}{2}x^3y^2\)

\(=-1.\frac{25x^3y^2}{8}\)

\(=-\frac{25x^3y^2}{8}\)