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Bài 1: 4Na+O2->2Na2O
(2): Na2O +H2O -> 2NaOH
(3): 2NaOH + BaCl2-> 2NaCl + Ba(OH)2
(4): NaCl + AgNO3-> AgCl + NaNO3
phần 2:
(1) 2NaOH + CO2-> Na2CO3 + H2O
(2) Na2CO3 +CaCl2- > CaCO3 + 2NaCl
(3) CaCO3-t0-> CaO + CO2
(4) CaO +H2O -> Ca(OH)2
(5) Ca(OH)2 + BaCl2-> Ba(OH)2 + CaCl2
Bài 1:
1) 4Na + O2 --to--➢ 2Na2O
Na2O + H2O → 2NaOH
2NaOH + 2HCl → 2NaCl + H2O
NaCl + AgNO3 → NaNO3 + AgCl
2) 2NaOH + CO2 → Na2CO3 + H2O
Na2CO3 + CaCl2 → 2NaCl + CaCO3
CaCO3 --to--➢ CaO + CO2
CaO + H2O → Ca(OH)2
Ca(OH)2 + 2HCl → CaCl2 + 2H2O
Câu 4:
\(n_{H_2SO_4}=\dfrac{200.19,6}{98.100}=0,4mol\)
\(n_{BaCl_2}=\dfrac{50.25}{208.100}\approx0,06mol\)
H2SO4+BaCl2\(\rightarrow\)BaSO4\(\downarrow\)+2HCl
-Tỉ lệ: \(\dfrac{0,4}{1}>\dfrac{0,06}{1}\rightarrow H_2SO_4dư\)
\(n_{H_2SO_4\left(pu\right)}=n_{BaSO_4}=n_{BaCl_2}=0,06mol\)
\(m_{BaSO_4}=0,06.233=13,98gam\)
\(n_{HCl}=2n_{BaCl_2}=2.0,06=0,12mol\)
\(n_{H_2SO_4\left(dư\right)}=0,4-0,06=0,34mol\)
\(m_{dd}=200+50-13,98=236,02gam\)
C%HCl=\(\dfrac{0,12.36,5}{236,02}.100\approx1,9\%\)
C%H2SO4=\(\dfrac{0,34.98}{236,02}.100\approx14,12\%\)
Câu 1:\(\%O=\dfrac{48}{2R+48}.100=47\rightarrow\)(2R+48).47=4800
\(\rightarrow\)94R+2256=4800\(\rightarrow\)94R=2544\(\rightarrow\)R=27(Al)
2FeS2+6O2-->Fe2O3+4SO2
2SO2+O2-->2SO3(V2O5,to)
SO3+H2O-->H2SO4
b)2Na+2H2O-->2NaOH+H2
2NaOH+H2SO4-->Na2SO4+2H2O
Na2SO4+Ba(OH)2-->BaSO4+2NaOH
2NaOH+CO2-->Na2CO3+H2O
Na2CO3+2HCl-->2NaCl+H2O+CO2
NaCl+AgNO3-->NaNO3+AgCl
C)
4Al+3O2-->2AL2O3
Al2O3+3H2SO4-->Al2(SO4)3+3H2O
Al2(SO4)3+3Ba(OH)2-->3BaSO4+2Al(OH)3
Al(OH)3+NaOH-->NaAlO2+H2O
NaALO2+H2O+CO2-->Al(OH)3+NaHCO3
Al(OH)3+HCl-->AlCl3+H2O
AlCl3+AgNO3-->Al(NO3)3+AgCl
a) 2FeS2 +11/2O2-----> 4SO2 +Fe2O3
2SO2+O2------> 2SO3
SO3+H2O----- -> H2SO4.
b) 2Na +2H2O-----> 2NaOH+H2
2NaOH+H2SO4----> Na2SO4 +2H2O
Na2SO4+Ba(OH)2----> NaOH +BaSO4
2NaOH+CO2----> Na2CO3+H2O
Na2CO3+2HCl----> 2NaCl+H2O+CO2
NaCl+AgNO3--->NaNO3+AgCl
c) 4Al+3O2--- -> 2Al2O3
Al2O3+3H2SO4 -> Al2(SO4)3+3H2O
Al2(SO4)3+6NaOH-> 2Al(OH)3+3Na2SO4
Al(OH)2+NaOH ----> NaAlO2+2H2O
NaAlO2+2H2O+CO2----> Al(OH)3 +NaHCO3
Al(OH)3+3NaOH----> AlCl3+3NaOH
Alcl3+3AgNO3---> Al(NO3)3+3NaCl
1.
a;CaO: canxi oxit
HNO3 : axit nitric
KOH : kali hidroxit
NaCl: natri clorua
b;
Mg + 2HCl -> MgCl2 + H2
Fe + 2HCl -> FeCl2 + H2
Mg + CuSO4 -> MgSO4 + Cu
Fe + CuSO4 -> FeSO4 + Cu
2.
4K + O2 -> 2K2O
K2O + H2SO4 -> K2SO4 + H2O
K2SO4 + BaCl2 -> 2KCl + BaSO4
Câu 1
a)
CaO là canxioxit
KOH là kalihiđroxit
NaCl là natriclorua
b)
Mg+ 2HCl→MgCl2+H2
Fe + 2HCl→FeCl2+ H2
Mg+ CuSO4→MgSO4+ Cu
Fe+ CuSO4→FeSO4+ Cu
a) CaO + 2HNO3. ---> Ca(NO3)2 + H2O
b) HCl + CuO ---> ..CuCl2 + H2O
c) P2O5. +3 H2O---> 2H3PO4
d) CO2 + 2NaOH ----> Na2CO3+ H2O
e) CaCO3 ---> .CaO. + CO2
f) 2KOH + H2SO4. ---> K2SO4 +2H2O
l) 2H2SO4đn + Cu ---> SO2 + CuSO4 +.2H2O
Chúc bạn học tốt
\(FeCO_3+2HCl\rightarrow FeCl_2+CO_2+H_2O\)
\(FeCl_2+2NaOH\rightarrow Fe\left(OH\right)_2+NaCl\)
\(2FeCl_2+Cl_2\rightarrow2FeCl_3\)
\(4Fe\left(OH\right)_2+2H_2O+O_2\rightarrow4Fe\left(OH\right)_3\)
\(CO_2+Ba\left(OH\right)_2\rightarrow Ba\left(HCO_3\right)_2\)
\(Ba\left(HCO_3\right)_2+NaOH\rightarrow BaCO_3+Na_2CO_3+H_2O\)
\(BaCO_3+2HCl\rightarrow CO_2+BaCl_2+H_2O\)
\(2FeCl_3+3Na_2CO_3+H_2O\rightarrow6NaCl+Fe_2\left(CO_3\right)_3\)
Bài 1:
a) K: 2K + 2HCl---> 2KCl+ H2
2K + 2H2O ---> 2KOH + H2 (nếu K dư)
Zn: Zn+ 2HCl--> ZnCl2 + H2
Cu: ko có pứ
AgNO3: AgNO3+ HCl ---> AgCl + HNO3
CuO : CuO + 2HCl --> CuCl2 + H2O
NaOH: NaOH + HCl --> NaCl + H2O
Na2SO4: ko có pứ
Mg(OH)2: Mg(OH)2 + 2HCl--> MgCl2 + 2H2O
K2CO3: K2CO3 + 2HCl --- > 2KCl + CO2 + H2O
Al2O3: Al2O3 + 6HCl --> 2AlCl3 + 3H2O
b) Na: 2Na + 2H2O --> 2NaOH
CO2: CO2 + Ba(OH)2 ---> BaCO3 + H2O (nếu Ba(OH)2 dư)
2CO2 + Ba(OH)2 ---> Ba(HCO3)2 (nếu CO2 dư)
H2SO4: Ba(OH)2 + H2SO4 --> BaSO4 + 2H2O
HCl: Ba(OH)2 + 2HCl ---> BaCl2 + H2O
MgSO4: MgSO4 + Ba(OH)2 --> Mg(OH)2 + BaSO4
Al2O3: Al2O3 + 3H2SO4 --> Al2(SO4)3 + 3H2O
NaCl: ko pứ
CuCl2: CuCl2 + Ba(OH)2 ---> Cu(OH)2 + BaCl2
c) K: 2K + 2H2O --> 2KOH + H2
Mg: ko pứ
H2SO4: Na2CO3 + H2SO4 --> Na2SO4 + CO2 + H2O
KOH: ko pứ
Ca(OH)2: Ca(OH)2 + Na2CO3 --> 2NaOH + CaCO3
BaCl2: BaCl2 + Na2CO3 --> 2NaCl + BaCO3
KCl: ko pứ
Bài 2: A: Fe2O3 B: FeCl3
D: Fe(OH)3 E: Fe2O3
4Fe + 3O2 ---> 2Fe2O3
Fe2O3 + 6HCl---> 2FeCl3+ 3H2O
FeCl3 + 3NaOH --> Fe(OH)3 + 3NaCl
2Fe(OH)3 ----> Fe2O3 + 3H2O