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\(3\frac{1}{2}+4\frac{5}{7}-5\frac{5}{14}=\frac{7}{2}+\frac{33}{7}-\frac{75}{14}=\frac{49}{14}+\frac{66}{14}-\frac{75}{14}=\frac{40}{14}=\frac{20}{7}\)
#Fox
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a: \(=\dfrac{3\cdot\left(6+4\right)}{6\cdot2}=\dfrac{3\cdot10}{6\cdot2}=\dfrac{30}{12}=\dfrac{5}{2}\)
b: \(=\dfrac{12\left(6-1\right)}{3\left(4+5\right)}=4\cdot\dfrac{5}{9}=\dfrac{20}{9}\)
\(\frac{15}{a}\cdot\frac{2}{3}\cdot\frac{3}{2}=\frac{5}{4}\)
\(\frac{15}{a}\cdot\frac{2}{3}=\frac{5}{4}:\frac{3}{2}\)
\(\frac{15}{a}\cdot\frac{2}{3}=\frac{5}{4}\cdot\frac{2}{3}\)
\(\frac{15}{a}\cdot\frac{2}{3}=\frac{10}{12}\)
\(\frac{15}{a}\cdot\frac{2}{3}=\frac{5}{6}\)
\(\frac{15}{a}=\frac{5}{6}:\frac{2}{3}\)
\(\frac{15}{a}=\frac{5}{6}\cdot\frac{3}{2}\)
\(\frac{15}{a}=\frac{15}{12}\)
Ta có: \(\frac{15}{a}=\frac{15}{12}\)
Mặt khác: 15 = 15 => a = 12
Vậy a tìm được bằng 12
\(\frac{4}{5}\cdot\frac{3}{7}+\frac{4}{5}\cdot\frac{6}{7}-\frac{4}{5}\cdot\frac{4}{14}\)
\(=\frac{4}{5}\cdot\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{14}\right)\)
\(=\frac{4}{5}\cdot1=\frac{4}{5}\)
#Louis