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Bài làm:
Ta có: \(\frac{9^2.\left(-4\right)^5.72}{5.\left(-6\right)^6}\cdot\frac{6^3.81.\left(-4\right)}{\left(-8\right)^6.3^9}\)
\(=\frac{3^2.-2^{10}.2^3.3^2.2^3.3^3.3^4.-2^2}{5.2^3.3^3.2^{18}.3^9}\)
\(=\frac{2^{18}.3^{11}}{2^{21}.3^{12}.5}\)
\(=\frac{1}{2^3.2.5}=\frac{1}{120}\)
\(\frac{25^5.2^{10}}{20^4.5^4}\)
=\(\frac{25^5.2^{10}}{20^4.25^2}\)
=\(\frac{25^3.2^{10}}{20^4}\)
=\(\frac{25^3.1024}{160000}\)
=\(\frac{25^3.4}{25^2}\)
=\(25.4\)
=100
#)Giải :
\(9^8:\left(27^3.81^2\right)=\left(3^2\right)^8:\left[\left(3^3\right)^3.\left(3^4\right)^2\right]=3^{16}:\left[3^9.3^8\right]\)
Đến đây ez rùi ^^
a) \(9^8=\left(3^2\right)^8=3^{16}\)
\(27^3=\left(3^3\right)^3=3^9\)
\(81^2=\left(3^4\right)^2=3^8\)
\(\Leftrightarrow3^{16}:\left(3^9.3^8\right)\)
\(\Leftrightarrow3^{16}:3^{17}\)
\(\Leftrightarrow3^{-1}=\frac{1}{3}\)
a) 76.12 + 24.12 - 200
= 12.(76+24)-200
= 12.100 -200
= 1200-200 = 1000
b) 3^4 . 36 + 4^3 . 81 -100
= 81.36 + 64.81 -100
= 81.(36+64)-100
=81.100-100
=8100-100 = 8000
a) 76.12 + 24.12 - 200
= 12.( 76+24 ) - 200
= 12.100 - 200
= 1200 - 200 = 1000
b) 3^4 . 36 + 4^3 . 81 - 100
= 81.36 + 64.81 - 100
= 81.(36+64) - 100
=81.100 - 100
=8100 - 100 = 8000
Học tốt!
\(\frac{27^2.8^5}{6^6.32^3}=\frac{\left(3^3\right)^2.\left(2^3\right)^5}{2^6.3^6.\left(2^5\right)^3}\)
\(=\frac{3^6.2^{15}}{2^6.3^6.2^{15}}\)
\(=\frac{1}{2^6}\)
Chú ý : Bạn nào làm nhanh , đấy đủ và đúng thì minh mới k cho đó nha
\(3^3\times9^3\times81\)
\(=3^{\text{3}}\times\left(3^2\right)^3\times9^2\)
\(=3^3\times3^6\times3^4=3^{13}\)
\(B=8^3\times81^4\div9^6\times32=\left(2^3\right)^3\times\left(3^4\right)^4\div\left(3^2\right)^6\times2^5=2^9\times3^{16}\div3^{12}\times2^5=2^{14}\times3^4\)
\(8^3.81^4:9^6.32=\left(2^3\right)^3.\left(3^4\right)^4:\left(3^2\right)^6.2^5=2^9.3^{16}:3^{12}.2^5=\left(2^9.2^5\right).\left(3^{16}:3^{12}\right)=2^{14}.3^4\)