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C.\(\frac{4^5.\left(1+1+1+1\right)}{3^5.\left(1+1+1\right)}.\frac{6^6}{2^{5+}2^5}=\frac{4^6}{3^6}.\frac{6^6}{2^5+2^5}=\frac{24^6}{3^6.\left(2^5+2^5\right)}=\frac{8^6}{2^5.\left(1+1\right)}\)=\(\frac{8^6}{2^6}\)=4^6=4096

a, \(\dfrac{4^2.4^3}{2^{10}}=\dfrac{4^5}{2^{10}}=\dfrac{\left(2^2\right)^5}{2^{10}}=\dfrac{2^{10}}{2^{10}}=1\)
b, \(\dfrac{2^7.9^3}{6^5.8^2}=\dfrac{2^7.\left(3^2\right)^3}{2^5.3^5.\left(2^3\right)^2}=\dfrac{2^7.3^6}{2^5.3^5.2^6}=\dfrac{3}{2^4}=\dfrac{3}{16}\)
c, \(\dfrac{9^7.5^6.125^9}{15^{15}.5^{18}}=\dfrac{3^{21}.5^6.5^{27}}{5^{15}.3^{15}.5^{18}}=\dfrac{3^{21}.5^{33}}{3^{15}.5^{33}}=3^6=729\)
d, \(\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\dfrac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\dfrac{2^{12}.3^9.\left(1+3.5\right)}{2^{11}.3^{11}.\left(2.3-1\right)}=\dfrac{2.16}{3^2.5}=\dfrac{32}{45}\)
Chúc bạn học tốt!!!

\(a,\left[2^{17}+16^2\right]\cdot\left[9^{15}-3^{15}\right]\cdot\left[2^4-4^2\right]\)
\(=\left[2^{17}+16^2\right]\cdot\left[9^{15}-3^{15}\right]\cdot\left[16-16\right]\)
\(=\left[2^{17}+16^2\right]\left[9^{15}-3^{15}\right]\cdot0=0\)
\(b,\left[8^{2017}-8^{2015}\right]\cdot\left[8^{2014}\cdot8\right]\)
\(=8^{2015}\left[8^2-1\right]\cdot8^{2015}\)
\(=8^{2015}\cdot63\cdot8^{2015}=8^{4030}\cdot63\)sửa lại câu b , có vấn đề rồi
\(c,\frac{2^8+8^3}{2^5\cdot2^3}=\frac{2^8+\left[2^3\right]^3}{2^5\cdot2^3}=\frac{2^8+2^9}{2^8}=\frac{2^8\left[1+2\right]}{2^8}=3\)
2.a, \(2^6=\left[2^3\right]^2=8^2\)
Mà 8 = 8 nên 82 = 82 hay 26 = 82
b, \(5^3=5\cdot5\cdot5=125\)
\(3^5=3\cdot3\cdot3\cdot3\cdot3=243\)
Mà 125 < 243 nên 53 < 35
c, 26 = [23 ]2 = 82
Mà 8 > 6 nên 82 > 62 hay 26 > 62
d, 7200 = [72 ]100 = 49100
6300 = \(\left[6^3\right]^{100}\)= 216100
Mà 49 < 216 nên 49100 < 216100 hay 7200 < 6300

\(a,\frac{(-10)^5}{3\cdot(-6)^4}=\frac{(-2\cdot5)^5}{3\cdot(-2\cdot3)^4}=\frac{(-2)^5\cdot5^5}{3\cdot(-2)^4\cdot3^4}=\frac{(-2)^5\cdot5^5}{(-2)^4\cdot3^5}=-2\cdot\frac{5^5}{3^5}=\frac{-6250}{243}\)
\(b,\frac{2^{15}\cdot9^4}{6^6\cdot8^3}=\frac{\left[2^3\right]^5\cdot\left[3^2\right]^4}{\left[3\cdot2\right]^6\cdot\left[2^3\right]^3}=\frac{2^{15}\cdot3^8}{3^6\cdot2^6\cdot2^9}=\frac{2^{15}\cdot3^8}{3^6\cdot2^{15}}=\frac{3^8}{3^6}=3^2=9\)
\(c,\left[1+\frac{2}{3}-\frac{1}{4}\right]\cdot\left[\frac{4}{5}-\frac{3}{4}\right]^2\)
\(=\left[\frac{12}{12}+\frac{8}{12}-\frac{3}{12}\right]\cdot\left[\frac{16}{20}-\frac{15}{20}\right]^2\)
\(=\frac{17}{12}\cdot\left[\frac{1}{20}\right]^2=\frac{17}{12}\cdot\frac{1^2}{20^2}=\frac{17}{12}\cdot\frac{1}{400}=\frac{17}{4800}\)
\(d,2^3+3\cdot\left[\frac{1}{2}\right]^0+\left[(-2)^2:\frac{1}{2}\right]\)
\(=8+3\cdot\frac{1^0}{2^0}+\left[4:\frac{1}{2}\right]\)
\(=8+3\cdot1+8=8+3+8=19\)

1)\(\frac{4^6.45}{2^4}=\frac{\left(2^2\right)^6.45}{2^4}=\frac{2^{12}.45}{2^4}=2^8.45=256.45=11520\)
2)\(\frac{8^5.16^3}{4^{13}}=\frac{8^5.\left(4^2\right)^3}{4^{13}}=\frac{8^5.4^6}{4^{13}}=\frac{8^5}{4^7}=\frac{\left(8^2\right)^2.8}{\left(4^3\right)^2.4}=\frac{64^2.8}{64^2.4}=\frac{8}{4}=2\)
3)Cái này bạn tự làm vì dễ rồi
4)\(\frac{45^{10}.5^{20}}{75^{15}}=\frac{\left(3^2.5\right)^{10}.5^{20}}{\left(5^2.3\right)^{15}}=\frac{3^{20}.5^{10}.5^{20}}{5^{30}.3^{15}}=\frac{3^{20}.5^{30}}{5^{30}.3^{15}}=3^5=243\)
Chúc bạn học tốt
Trả lời:
1,\(\frac{4^6\times45}{2^4}=\frac{\left(2^2\right)^6\times45}{2^4}\)
\(=\frac{2^{12}\times45}{2^4}\)
\(=2^8\times45\)
\(=256\times45\)
\(=11520\)
2,\(\frac{8^5\times16^3}{4^{13}}=\frac{\left(2^3\right)^5\times\left(2^4\right)^3}{\left(2^2\right)^{13}}\)
\(=\frac{2^{15}\times2^{12}}{2^{26}}\)
\(=\frac{2^{27}}{2^{26}}\)
\(=2\)
3,\(\frac{2^{10}\times13+2^{10}\times65}{2^8\times104}=\frac{2^{10}\times\left(13+65\right)}{2^8\times104}\)
\(=\frac{2^{10}\times78}{2^8\times104}\)
\(=\frac{2^2\times3}{4}\)
\(=\frac{4\times3}{4}\)
\(=3\)
4,\(\frac{45^{10}\times5^{20}}{75^{15}}=\frac{\left(5\times9\right)^{10}\times5^{20}}{\left(3\times25\right)^{10}}\)
\(=\frac{\left(5\times3^2\right)^{10}\times5^{20}}{\left(3\times5^2\right)^{15}}\)
\(=\frac{5^{10}\times3^{20}\times5^{20}}{3^{15}\times5^{30}}\)
\(=\frac{5^{30}\times3^{20}}{3^{15}\times5^{30}}\)
\(=3^5=243\)
Học tốt
Bài làm :
Ta có :
\(b=\left(-1\right)^{2020}.\left(\frac{2}{5}\right)^3.\left(\frac{15}{4}\right)^2\div\left(\frac{15^2}{2^4}\right).\left(\frac{2}{5}\right)^3\)
\(b=1.\left[\left(\frac{2}{5}\right)^3.\left(\frac{2}{5}\right)^3\right].\left[\left(\frac{15^2}{4^2}\right)\div\frac{15^2}{2^4}\right]\)
\(b=\left(\frac{2}{5}\right)^6.\left(\frac{15^2}{16}\div\frac{15^2}{16}\right)\)
\(b=\left(\frac{2}{5}\right)^6.1=\left(\frac{2}{5}\right)^6\)