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a) /x+\(\frac{4}{15}\)/ - / -3,75/ = -2,15
=> \(\orbr{\begin{cases}x+\frac{4}{15}+3,75=-2,15\\x+\frac{4}{15}+3,75=2,15\end{cases}}\)
=> ....v.....v giải ra ( từng th )
bài khác tương tự
a) \(\left|x-1,7\right|+\dfrac{1}{2}=23\)
\(\left|x-1,7\right|=22,5\)
\(\Rightarrow x-1,7=\pm22,5\)
\(\Rightarrow x=\left\{24,2;-20,8\right\}\)
b) \(\left|x+\dfrac{4}{15}\right|-\left|3,75\right|=-\left|2,15\right|\)
\(\left|x+\dfrac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\dfrac{4}{15}\right|=-2,15+3,75\)
\(\left|x+\dfrac{4}{15}\right|=1,6\)
\(\Rightarrow x+\dfrac{4}{15}=\pm1,6\)
\(\Rightarrow x=\left\{\dfrac{4}{3};-\dfrac{28}{15}\right\}\)
a, 11/13 - ( 5/42 - x ) = - (5/28 - 11/13)
11/13 - (5/42 - x) = - 5/28 + 11/13
- (5/42 - x) + 5/28 = -11/13 + 11/13
- 5/42 + x + 5/28 = 0
- 5/42 + x = 0 - 5/28
- 5/42 + x = - 5/28
x = -5/28 +5/42
x = - 5/84
b, / x + 4/15 \ - / - 3,75 \ = - / - 2,15 \
./ x + 4/15 \ - 3,75 = - 2,15
/ x + 4/15 \ = -2,15 + 3,75
/ x + 4/15 \ = 1,6
x + 4 / 15 = 1,6 hoặc x+ 4/15 = - 1,6
x = 1,6 - 4/15 x = - 1,6 -4/15
x = 4/3 x = -28/15
Vậy x = 4/3 hoặc x = - 28/15
c, ( 0,25 - 30% x ) . 1/3 = 1/4 - 31/6
( 1/4 - 3/10 x ) . 1/3 = - 59/12
( 1/4 - 3/10 x ) = - 59/12 : 1/3
1/4 - 3/10 x = - 59/4
3/10 x = 1/4 + 59/4
3/10 x = 15
x = 15 : 3/10
x = 50
d, ( x - 1/2 ) : 1/3 + 5/7 = 68/7
( x - 1/2 ) : 1/3 = 68/7 - 5/7
( x - 1/2 ) : 1/3 = 63/7
( x - 1/2 ) = 63/7 . 1/3
x -1/2 = 3
x = 3 + 1/2
x = 7/2
a: \(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=-2.15+3.75=1.6=\dfrac{8}{5}\)
=>x+4/15=8/5 hoặc x+4/15=-8/5
=>x=4/3 hoặc x=-28/15
c: =>x-y=0 và y+9/25=0
=>x=y=-9/25
d: =>-1/3<x-3/5<1/3
=>4/15<x<14/15
e: =>|x+5,5|>5,5
=>x+5,5>5,5 hoặc x+5,5<-5,5
=>x>0 hoặc x<-11
a) \(\left|x\right|=0\Rightarrow x=0\)
b) \(\left|x\right|=\frac{1}{5}\Rightarrow x=\pm\frac{1}{5}\)
c) +d) (2 phần này đề giống nhau à bạn?) \(\left|x\right|=1,357\Rightarrow x=\pm1,357\)
e) \(\left|x\right|=3\frac{1}{4}\Rightarrow x=\pm3\frac{1}{4}\)
g) \(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=\frac{8}{5}\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=\frac{-8}{5}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=\frac{-28}{15}\end{cases}}\)
f) \(\left|x+\frac{3}{4}\right|-\frac{1}{2}=0\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{3}{4}=\frac{1}{2}\\x+\frac{3}{4}=\frac{-1}{2}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}-\frac{3}{4}\\x=\frac{-1}{2}-\frac{3}{4}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{4}\\x=\frac{-5}{4}\end{cases}}\)
\(a,|x|=0\)
=> x = 0
\(b,|x|=\frac{1}{5}\)
=> \(\orbr{\begin{cases}x=\frac{1}{5}\\x=-\frac{1}{5}\end{cases}}\)
\(c,|x|=1,357\)
=> \(\orbr{\begin{cases}x=1,357\\x=-1,357\end{cases}}\)
\(d,|x|=1\cdot357\)
=> \(\orbr{\begin{cases}x=357\\x=-357\end{cases}}\)
\(e,|x|=3\)
=> \(\orbr{\begin{cases}x=3\\x=-3\end{cases}}\)
\(|x|=\frac{1}{4}\)
=> \(\orbr{\begin{cases}x=\frac{1}{4}\\x=-\frac{1}{4}\end{cases}}\)
\(g,|x+\frac{4}{15}|-|-3,75|=-|-2,15|\)
=> \(|x+\frac{4}{15}|-3,75=-2,15\)
=> \(|x+\frac{4}{15}|=1,6=\frac{8}{5}\)
=> \(\orbr{\begin{cases}x+\frac{4}{15}=\frac{24}{15}\\x+\frac{4}{15}=-\frac{24}{15}\end{cases}}\) => \(\orbr{\begin{cases}x=\frac{20}{15}=\frac{4}{3}\\x=-\frac{28}{15}\end{cases}}\)
\(f,|x+\frac{3}{4}|-\frac{1}{2}=0\)
=> \(|x+\frac{3}{4}|=\frac{1}{2}\)
=> \(\orbr{\begin{cases}x+\frac{3}{4}=\frac{2}{4}\\x+\frac{3}{4}=-\frac{2}{4}\end{cases}}\)
=> \(\orbr{\begin{cases}x=-\frac{1}{4}\\x=-\frac{5}{4}\end{cases}}\)