Question

[nguyễn trường giang]

A=căn3 -căn6 / 1- căn 2    -  2+ căn8 /1 + căn 2

Answer 1

[Kiyotaka Ayanokoji]

Trả lời:

\(A=\sqrt{3}-\frac{\sqrt{6}}{1-\sqrt{2}}-\frac{2+\sqrt{8}}{1+\sqrt{2}}\)

\(A=\sqrt{3}+\frac{\sqrt{6}}{\sqrt{2}-1}-\frac{2\sqrt{2}+2}{\sqrt{2}+1}\)

\(A=\sqrt{3}+\frac{\sqrt{6}.\left(\sqrt{2}+1\right)}{2-1}-\frac{2.\left(\sqrt{2}+1\right)}{\sqrt{2}+1}\)

\(A=\sqrt{3}+\sqrt{6}.\left(\sqrt{2}+1\right)-2\)

\(A=\sqrt{3}+\sqrt{12}+\sqrt{6}-2\)

\(A=\sqrt{3}+2\sqrt{3}+\sqrt{6}-2\)

\(A=3\sqrt{3}+\sqrt{6}-2\)

Answer 2

[Kiyotaka Ayanokoji]

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